CODEWITHSUNDEEP
functionjuliascoping
L. Mann
L. Mann

Reputation: 143

In Julia, why can "if false" statements in local scope modify function definitions?

In Julia 1.4.1, if I define a function in a global scope, modifications after "if false" statements do not affect it, as expected:

test()=0
if false
  test()=1
end

println(test())

This prints "0", as it should. However, when I enclose this code within a local scope, the behavior changes:

function main()
  test()=0
  if false
    test()=1
  end

  println(test())
end

main()

This now prints "1" which I did not expect. If I change "test" to be an array or a float I observe no modification as expected, i.e. the problem does not occur. Why does Julia behave this way for functions?

Upvotes: 10

Views: 163

Answers (1)

mbauman
mbauman

Reputation: 31342

The solution is to use anonymous functions in cases like this:

function main()
  test = () -> 0
  if false
    test = () -> 1
  end

  println(test())
end

julia> main()
0

As for the why, this gets to the core of what it means to define and redefine a particular method of a function.

Upvotes: 5

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