draeway
draeway

Reputation: 5

HOW TO: Python: Countdown until matching digits?

So we have to complete a task where we enter a digit from 20-98 (inclusive). The task is to make it so that it stops counting down (or breaks) whenever there's a same-digit number (88,77,66,55,44,33,22). I am able to make it pass tests if I enter 93, but not for other numbers (for ex. 30).

If we enter a digit (for example 93), the output would be:

93
92
91
90
89
88

is my code so far:

x = int(input())


while 20 <= x <= 98:
    print(x, end='\n')
    x -= 1

    if x < 88:
        break
    elif x < 77:
        break
    elif x < 66:
        break
    elif x < 55:
        break
    elif x < 44:
        break
    elif x < 33:
        break
    elif x < 22:
        break
    elif x < 11:
        break

else:
    print("Input must be 20-98")

I was wondering how I need to change my code so that it can apply to all numbers, and so I do0n't have to write so many if-else statements for all the possible same-digit numbers.

Upvotes: 0

Views: 11316

Answers (4)

Curtis Mann
Curtis Mann

Reputation: 1

x = int(input())

while 11 <= x <= 100:
    print(x, end='\n')
    if x % 11 == 0:
        break
    x -= 1

else:
    print("Input must be 11-100") #works for 4.25 DAT210

Upvotes: -2

StockJanitor
StockJanitor

Reputation: 19

x = int(input())

if (x >= 20 and x <= 98):
    while (not (x % 10 == x // 10)):
        print(x)
        x -= 1
    print(x)
else:
    print('Input must be 20-98')

Upvotes: 0

Leo Schwanke II
Leo Schwanke II

Reputation: 1

user_int = int(input())

if 20 <= user_int <=98:

    print(user_int)

    while not user_int % 11 == 0:
        user_int -= 1
        print(user_int)

else:
    print("Input must be 20-98")

Upvotes: 0

sahinakkaya
sahinakkaya

Reputation: 6056

You can use the modulo operator (%) which yields the remainder from a division.

x = int(input())

while 20 <= x <= 98:
    print(x, end='\n')
    if x % 11 == 0:
        break
    x -= 1

else:
    print("Input must be 20-98")

Upvotes: 1

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