CODEWITHSUNDEEP
swiftswift-keypath
TruMan1
TruMan1

Reputation: 36158

Shorthand key path in switch statement?

I have a method that takes a key path for a type, however it is giving me a compile error when I try to use the shorthand version of the key path.

Here's what I'm trying to do:

struct MyType {
    let prop1: String
    let prop2: Int
    let prop3: Bool
}

func test(_ keyPath: PartialKeyPath<MyType>) {
    switch keyPath {
    case \MyType.prop1:
        print("prop1")
    case \MyType.prop2:
        print("prop1")
    case \MyType.prop3:
        print("prop1")
    default:
        break
    }
}

test(\MyType.prop1)

In the switch statement, is it possible to do case \.prop1 instead of specifying the root? When I try this I get this error:

Type of expression is ambiguous without more context

It is also forcing me to specify a default case even though I've specified all the properties of the type. Is there a reason for this as well? Thanks for any help.

Upvotes: 0

Views: 230

Answers (0)

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