Reputation: 1677
I have a 2D array that looks like this:
[[0.1, 0.2, 0.4, 0.6, 0.9]
[0.3, 0.7, 0.8, 0.3, 0.9]
[0.7, 0.9, 0.4, 0.6, 0.9]
[0.1, 0.2, 0.6, 0.6, 0.9]]
And I want to save the indices where the array is higher than 0.6 but I also want to keep the value of that position, so the output would be:
[0, 3, 0.6]
[0, 4, 0.9]
[1, 2, 0.7]
and so on.
To get the indices I did this:
x = np.where(PPCF> 0.6)
high_pc = np.asarray(x).T.tolist()
but how do I keep the value in a third position?
Upvotes: 1
Views: 111
Reputation: 1195
import numpy as np
arr = np.array([[0.1, 0.2, 0.4, 0.6, 0.9],
[0.3, 0.7, 0.8, 0.3, 0.9],
[0.7, 0.9, 0.4, 0.6, 0.9],
[0.1, 0.2, 0.6, 0.6, 0.9]])
rows, cols = np.where(arr > 0.6) # Get rows and columns where arr > 0.6
values = arr[rows, cols] # Get all values > 0.6 in arr
result = np.column_stack((rows, cols, values)) # Stack three columns to create final array
"""
Result -
[ 0. 4. 0.9]
[ 1. 1. 0.7]
[ 1. 2. 0.8]
[ 1. 4. 0.9]
[ 2. 0. 0.7]
[ 2. 1. 0.9]
[ 2. 4. 0.9]
[ 3. 4. 0.9]]
"""
You can convert result into a list.
Upvotes: 0
Reputation: 1744
Simple, no loops:
x = np.where(PPCF > 0.6) # condition to screen values
vals = PPCF[x] # find values by indices
np.concatenate((np.array(x).T, vals.reshape(vals.size, 1)), axis = 1) # resulting array
Feel free to convert it to a list.
Upvotes: 3
Reputation: 76
You could just run a loop along the columns and rows and check if each element is greater than the threshold and save them in a list.
a = [[0.1, 0.2, 0.4, 0.6, 0.9],
[0.3, 0.7, 0.8, 0.3, 0.9],
[0.7, 0.9, 0.4, 0.6, 0.9],
[0.1, 0.2, 0.6, 0.6, 0.9]]
def find_ix(a, threshold = 0.6):
res_list = []
for i in range(len(a)):
for j in range(len(a[i])):
if a[i][j] >= threshold:
res_list.append([i, j, a[i][j]])
return res_list
print("Resulting list = \n ", find_ix(a))
Upvotes: 1
Reputation: 887
This should work :
x = np.where(PPCF> 0.6)
high_pc = np.asarray(x).T.tolist()
for i in high_pc:
i.append(float(PPCF[i[0],i[1]]))
Upvotes: 1