Reputation: 75
I have an XML area.xml
<area>
<controls>
<internal>yes</internal>
</controls>
<schools>
<school id="001"/>
<time>2020-05-18T14:21:00Z</time>
<venture index="5">
<venture>
<basicData type="class">
<wage numberOfDollars="13" Correction="4.61">
<tax>70</tax>
</wage>
</basicData>
</venture>
</venture>
<venture index="9">
<venture>
<basicData type="class">
<wage numberOfDollars="13" Correction="5.61">
<tax>70</tax>
</wage>
</basicData>
</venture>
</venture>
<school id="056"/>
<time>2020-05-18T14:21:00Z</time>
<venture index="5">
<venture>
<basicData type="class">
<wage numberOfDollars="13">
<tax>70</tax>
</wage>
</basicData>
</venture>
</venture>
<venture index="9">
<venture>
<basicData type="class">
<wage numberOfDollars="13">
<tax>70</tax>
</wage>
</basicData>
</venture>
</venture>
</schools>
What i am trying to achieve with Python: in a school node there are multiple wage nodes(leaves). if a wage node(leave)(1 or more) has an attribute called Correction i want the attribute value of the school node.
So the outcome of my script should be: 001 because this school has the attribute Correction in the wage node(leave)
First i tried it using ETree
import xml.etree.ElementTree as ET
data_file = 'area.xml'
tree = ET.parse(data_file)
root = tree.getroot()
t1 = "school"
t2 = "wage"
for e1, e2 in zip(root.iter(t1), root.iter(t2)):
if hasattr(e2,'Correction'):
e2.Correction
print (e1.attrib['id'])
but that didn't work. Now I am trying to reach my goal using minidom but I find it quite hard.
This is my code so far:
from xml.dom import minidom
doc = minidom.parse("area.xml")
staffs = doc.getElementsByTagName("wage")
for wage in staffs:
sid = wage.getAttribute("Correction")
print("wage:%s" %
(sid))
the output gives all values of the wage attribute Correction:
wage:4.61
wage:5.61
wage:
wage:
Which is obviously far from correct.
i could use some help getting me in the right direction
i am using python 3
thank you in advance
Upvotes: 0
Views: 700
Reputation: 52858
in a school node there are multiple wage nodes
Not really. The school
elements are empty. The venture
siblings have the wage
descendants. Since wage
is not a descendant of school
, this makes it a little tricky to select the corresponding school
.
If you can use lxml you could use XPath to select the wage
elements that have a Correction
attribute and then select the first preceding school
element and get its id
attribute...
from lxml import etree
tree = etree.parse("area.xml")
schools_with_corrected_wages = set()
for corrected_wage in tree.xpath(".//wage[@Correction]"):
schools_with_corrected_wages.add(corrected_wage.xpath("preceding::school[1]/@id")[0])
print(schools_with_corrected_wages)
This prints:
{'001'}
You could also use lxml to process the XML with XSLT...
XSLT 1.0 (test.xsl)
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:strip-space elements="*"/>
<xsl:key name="corrected_wage_by_school" match="wage[@Correction]" use="preceding::school[1]/@id"/>
<xsl:template match="/">
<xsl:for-each select="//school[key('corrected_wage_by_school',@id)]">
<xsl:value-of select="concat(@id,'
')"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Python
from lxml import etree
tree = etree.parse("area.xml")
xslt = etree.parse("test.xsl")
result = tree.xslt(xslt)
print(result)
This prints...
001
Upvotes: 2
Reputation: 2469
Here's a less clever way.
from simplified_scrapy import SimplifiedDoc, req, utils
html = utils.getFileContent("area.xml")
doc = SimplifiedDoc(html)
schools = doc.selects('school') # Get all schools
n = len(schools)
i = 0
while i < n - 1:
school = schools[i]
school1 = schools[i + 1]
h = doc.html[school._end:school1._start] # Get data between two schools
staffs = doc.getElementsByReg(' Correction="', tag='wage', html=h)
if staffs:
print(school.id, staffs.Correction)
i += 1
last = schools[n - 1]
h = doc.html[last._end:]
staffs = doc.getElementsByReg(' Correction="', tag='wage', html=h)
if staffs:
print(last.id, staffs.Correction)
Result:
001 ['4.61', '5.61']
Upvotes: 0