Reputation: 101
I´m scraping the new articles from this site https://nypost.com/search/China+COVID-19/page/2/?orderby=relevance I used for-loop to get the content of each news article, but I couldn´t able to combine paragraphs for each article. My goal is to store each article in a string, and all the strings should be stored in myarticle list.
When I print(myarticle[0]), it gives me all the articles. I expect it should give me one single article.
Any helps would be appreciated!
for pagelink in pagelinks:
#get page text
page = requests.get(pagelink)
#parse with BeautifulSoup
soup = bs(page.text, 'lxml')
containerr = soup.find("div", class_=['entry-content', 'entry-content-read-more'])
articletext = containerr.find_all('p')
for paragraph in articletext:
#get the text only
text = paragraph.get_text()
paragraphtext.append(text)
#combine all paragraphs into an article
thearticle.append(paragraphtext)
# join paragraphs to re-create the article
myarticle = [''.join(article) for article in thearticle]
print(myarticle[0])
For clarification purpose, the full code is attached below
def scrape(url):
user_agent = {'user-agent': 'Mozilla/5.0 (Windows NT 10.0; WOW64; Trident/7.0; Touch; rv:11.0) like Gecko'}
request = 0
urls = [f"{url}{x}" for x in range(1,2)]
params = {
"orderby": "relevance",
}
pagelinks = []
title = []
thearticle = []
paragraphtext = []
for page in urls:
response = requests.get(url=page,
headers=user_agent,
params=params)
# controlling the crawl-rate
start_time = time()
#pause the loop
sleep(randint(8,15))
#monitor the requests
request += 1
elapsed_time = time() - start_time
print('Request:{}; Frequency: {} request/s'.format(request, request/elapsed_time))
clear_output(wait = True)
#throw a warning for non-200 status codes
if response.status_code != 200:
warn('Request: {}; Status code: {}'.format(request, response.status_code))
#Break the loop if the number of requests is greater than expected
if request > 72:
warn('Number of request was greater than expected.')
break
#parse the content
soup_page = bs(response.text, 'lxml')
#select all the articles for a single page
containers = soup_page.findAll("li", {'class': 'article'})
#scrape the links of the articles
for i in containers:
url = i.find('a')
pagelinks.append(url.get('href'))
#scrape the titles of the articles
for i in containers:
atitle = i.find(class_ = 'entry-heading').find('a')
thetitle = atitle.get_text()
title.append(thetitle)
for pagelink in pagelinks:
#get page text
page = requests.get(pagelink)
#parse with BeautifulSoup
soup = bs(page.text, 'lxml')
containerr = soup.find("div", class_=['entry-content', 'entry-content-read-more'])
articletext = containerr.find_all('p')
for paragraph in articletext:
#get the text only
text = paragraph.get_text()
paragraphtext.append(text)
#combine all paragraphs into an article
thearticle.append(paragraphtext)
# join paragraphs to re-create the article
myarticle = [''.join(article) for article in thearticle]
print(myarticle[0])
print(scrape('https://nypost.com/search/China+COVID-19/page/'))
Upvotes: 2
Views: 899
Reputation: 2035
You keep appending to an existing list [], it keeps growing, you need to clear it every loop.
articletext = containerr.find_all('p')
for paragraph in articletext:
#get the text only
text = paragraph.get_text()
paragraphtext.append(text)
#combine all paragraphs into an article
thearticle.append(paragraphtext)
# join paragraphs to re-create the article
myarticle = [''.join(article) for article in thearticle]
Should be something like
articletext = containerr.find_all('p')
thearticle = [] # clear from the previous loop
paragraphtext = [] # clear from the previous loop
for paragraph in articletext:
#get the text only
text = paragraph.get_text()
paragraphtext.append(text)
thearticle.append(paragraphtext)
myarticle.append(thearticle)
But you could simplify it more to:
article = soup.find("div", class_=['entry-content', 'entry-content-read-more'])
myarticle.append(article.get_text())
Upvotes: 3