CODEWITHSUNDEEP
c++operator-overloading
user13575381
user13575381

Reputation:

C++ operator overloading not possible with **

Suppose I have a class called Complex, why I'm allowed to define the following function:

Complex operator+(Complex& c1, Complex& c2);

But I can't write:

Complex operator**(Complex& c1, Complex& c2);//for power

Upvotes: 1

Views: 144

Answers (2)

Christina
Christina

Reputation: 56

** is not a valid C++ operator on its own, it is simply two * operators with no whitespace. We cannot create new operators in C++, but operator* can be overloaded as an unary or a binary operator. operator* can be implemented as a non-member function, member function, or friend function, depending on the class structure. Below is an example of operator* implemented as a binary, non-member function, which returns a new Example object.

struct Example {
    int x;
};

Example operator*(Example a, const Example& b){
    return a *= b;
}

Upvotes: 2

ChrisMM
ChrisMM

Reputation: 10022

From over.oper, you can see which operators can be overloaded. You will notice that ** is not one of the valid operators to overload. There is, however, the ^ operator you can use (although it's usually meant for bitwise)

As mentioned in the comments, you cannot create new operators this way, so you cannot make a new one for **

Upvotes: 0

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