CODEWITHSUNDEEP
c#moq
Jez
Jez

Reputation: 29993

Allow *any* parameter value when verifying in Moq?

I'm verifying that a method was called with Moq, but it's quite a complex method signature and I just care about the value of one particular argument. I know Moq has It.IsAny<T>(), but even then you still have to specify what type the argument should be. Is there a way to just say "I don't care what was passed as this parameter, in terms of type OR value"?

Upvotes: 1

Views: 654

Answers (2)

rgvlee
rgvlee

Reputation: 3193

As @StriplingWarrior mentioned you've got to specify the arguments when using Verify.

However Moq does provide the Invocations sequence (unsure what version it was introduced, YMMV) so it is possible to basically do what you're asking.

For the following interface:

public interface IFoo
{
    public void Sum(int a, int b, out int sum);
}

... the following will assert that the Sum method was invoked once - without specifying any parameters.

var fooMock = new Mock<IFoo>();
var foo = fooMock.Object;

foo.Sum(1, 2, out var sum);

Assert.That(fooMock.Invocations.Count(x => x.Method.Name.Equals(nameof(IFoo.Sum))), Is.EqualTo(1));

Each invocation entry has the method, arguments etc so you can build complex matches.

Upvotes: 1

StriplingWarrior
StriplingWarrior

Reputation: 156504

There isn't a way to do what you're asking, because the Setup argument is an expression that represents strongly-typed C#. For example, consider the following approach:

void Main()
{
    Setup(() => Foo(Any()));
}

void Setup(Expression<Action> expression)
{
}

void Foo(int i)
{
}

object Any() 
{
    throw new NotImplementedException();
}

This code doesn't compile, because Any() returns an object and Foo() requires an int argument.

If we try to change Any() to return dynamic:

dynamic Any() {
    throw new NotImplementedException();
}

This produces the following error:

CS1963 An expression tree may not contain a dynamic operation

There's simply no way do make this expression generation work for every possible type without requiring a generic argument.

Upvotes: 3

Related Questions