CODEWITHSUNDEEP
php
Captain_Stag
Captain_Stag

Reputation: 57

<?php if function, search for a string that contains data

Hope all is well.

I'm wanting to display a series of badges which would display different images based on a field which contains a specific string. For example, something like this (although I'm aware that this is probably not correct)

            <?php if (stripos($business, "local") !== false) 
echo "badge-icon1.png"; ?>
        <?php if (stripos($business, "interstate") !== false) 
echo "badge-icon2.png"; ?>
        <?php if (stripos($business, "national") !== false) 
echo "badge-icon3.png"; ?>
        <?php if (stripos($business, "international") !== false) 
echo "badge-icon4.png"; ?>

I'm familiar with the stripos function, although I'm not sure whether or not it is suitable for an array of alternative scenarios based on if one field contains one of a few string options.

Is there an alternative method which may be a little more suitable?

Thank you for your assistance!

Upvotes: 1

Views: 34

Answers (1)

Nick
Nick

Reputation: 147176

stripos isn't really suitable here as it will match national in both national and international. If the entire $business string is the word local or interstate etc. you might find an array easier to work with:

$badges = array('local' => 'badge-icon1.png',
                'interstate' => 'badge-icon2.png',
                'national' => 'badge-icon3.png',
                'international' => 'badge-icon2.png'
                );
echo $badges[$business] ?? '';

If $business might have uppercase characters in it (e.g. Local), use strtolower($business) as the array index:

echo $badges[strtolower($business)] ?? '';

Also, if you want to have a default image for when $business doesn't match one of the 4 names, you can put that in the echo:

echo $badges[$business] ?? 'badge-placeholder.png';

Upvotes: 2

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