CODEWITHSUNDEEP
linuxcommand-lineextractping
Sam8000
Sam8000

Reputation: 13

Extract only integer milliseconds from linux commandline ping

I try to extract just integer number of milliseconds from continuous ping output in OpenWRT commandline. Example from ping 8.8.8.8

64 bytes from 8.8.8.8: seq=6 ttl=55 time=6.356 ms
64 bytes from 8.8.8.8: seq=7 ttl=55 time=6.520 ms
...

Desire output should looks like this:

6
6
...

Just integer (left part of number). Without fraction part and wihout dot.

I tried to cut output using pipes, firstly cutting equal signs ping 8.8.8.8 | cut -d '=' -f 4 which works

6.389 ms
6.051 ms
...

Then cutting also dots to get integer only ping 8.8.8.8 | cut -d "=" -f4 | cut -d '.' -f1 but then no output shows at all. I tried also using awk but when I use more than one pipe with those commands, there is no output. Could you show me how to do that.

Upvotes: 1

Views: 689

Answers (2)

George Pavelka
George Pavelka

Reputation: 2329

My solution uses simple sed replacement trimming decimals and discarding all surrounding string.

ping 8.8.8.8 | sed 's/.\+ time=\([0-9]\+\).\+/\1/'

Sample output:

PING 8.8.8.8 (8.8.8.8) 56(84) bytes of data.
42
50
51
39

The following solution only trims the decimals. Same thing.

ping 8.8.8.8 | sed 's/\.[0-9]\+ ms$/ ms/'

Sample output:

PING 8.8.8.8 (8.8.8.8) 56(84) bytes of data.
64 bytes from 8.8.8.8: icmp_seq=1 ttl=113 time=56 ms
64 bytes from 8.8.8.8: icmp_seq=2 ttl=113 time=221 ms
64 bytes from 8.8.8.8: icmp_seq=3 ttl=113 time=39 ms
64 bytes from 8.8.8.8: icmp_seq=4 ttl=113 time=37 ms

Upvotes: 0

mivk
mivk

Reputation: 14834

You can pipe the output through perl (for example) and use a simple regex:

ping -c3 8.8.8.8 | perl -nle '/time=(\d+)/ && print $1'

This will print the integer part.

You could also round the milliseconds to the nearest integer with printf

ping -c3 8.8.8.8 | perl -ne '/time=([\d\.]+) ms/ && printf "%.0f\n", $1'

Upvotes: 1

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