CODEWITHSUNDEEP
regexstringjava-6replaceall
user12813675
user12813675

Reputation:

Hyphen between letter and number

I need a function to put a hyphen where letters finish and numbers start or when numbers finish and letters start, for example, 1234GRR to 1234-GRR.

I am using Java 6.

I have this, but this just puts a hyphen everwhere.

public static String addHyphen(String word) {
    StringBuilder longer = new StringBuilder(word.substring(0,1));
    for (int i = 1; i < word.length(); i++) {
      longer.append("-" + word.charAt(i));
    }
    return longer.toString();
}

Can anyone help me? Thanks!

Upvotes: 0

Views: 646

Answers (3)

Arvind Kumar Avinash
Arvind Kumar Avinash

Reputation: 79435

You can do it using regex arguments as shown below:

public class Main {
    public static void main(String[] args) {
        // Test
        String[] testStrs = { "1234GRR", "GRR1234", "Hello", "Hello1234World", "1234GRR1234GRR" };
        for (String s : testStrs) {
            System.out.println(addHyphen(s));
        }
    }

    public static String addHyphen(String word) {
        String str = null;
        if (word != null) {
            str = word.replaceAll("([0-9]+)([A-Za-z]+)", "$1-$2");
            str = str.replaceAll("([A-Za-z]+)([0-9]+)", "$1-$2");
        }
        return str;
    }
}

Output:

1234-GRR
GRR-1234
Hello
Hello-1234-World
1234-GRR-1234-GRR

Note: $1 and $2 refer to the first and second capturing group respectively.

Upvotes: 0

amrtaweel
amrtaweel

Reputation: 96

Try this:

public static String addHyphen(String word) {
          boolean words=false;
          boolean number=false;
          String end=new String();
            for (int i = 0; i < word.length(); i++) {
                if (word.substring(i,i+1).matches("[1-9+]")&number==false){
                    number=true;
                    words=false;
                    end=end+"-"+word.substring(i,i+1);
                }else if (word.substring(i,i+1).matches("[a-zA-Z]")&words==false){
                   number=false;
                   words=true;
                    end=end+"-"+word.substring(i,i+1);
                }else {
                    end=end+word.substring(i,i+1); 
                }
            }
            return end.substring(1);
        }

Upvotes: 1

Andreas
Andreas

Reputation: 159165

The simplest solution would be to use a regex, assuming of course that you know regex. To locate a place between two characters, we use (?<=X) zero-width positive lookbehind and (?=X) zero-width positive lookahead.

public static String addHyphen(String word) {
    return word.replaceAll("(?i:(?<=[a-z])(?=[0-9])|(?<=[0-9])(?=[a-z]))", "-");
}

Test

System.out.println(addHyphen("1234GRR1234GRR"));

Output

1234-GRR-1234-GRR

For full Unicode definition of "letters" and "numbers", use this regex instead:

"(?<=\\p{L})(?=\\p{N})|(?<=\\p{N})(?=\\p{L})"

Test

System.out.println(addHyphen("1234FooⅯⅭⅭⅩⅩⅩⅣḞõô"));

Output

1234-Foo-ⅯⅭⅭⅩⅩⅩⅣ-Ḟõô

Upvotes: 4

Related Questions