Reputation: 129
I am trying to run a ORDER BY query but I want the output to be ordered according to a custom scheme. In SQL this is often done with a case system, but depending on the DB there are also other implementations. How would I achieve the sorting explained below with GridDB?
Lets assume my GridDB lists all the animals that are in a zoo and how many of each live there, I would like all the animals of which there are 4 or more, by size, smallest first (mouse), largest last (elephant).
Things I tried:
$query = $col->query("SELECT * WHERE count >= 4 ORDER BY CASE
WHEN 'mouse' THEN 1
WHEN 'cat' THEN 2
WHEN 'dog' THEN 3
WHEN 'elephant' THEN 4
ELSE 5
END");
$query = $col->query("SELECT * WHERE count >= 4 ORDER BY FIND_IN_SET(animal, 'mouse, cat, dog, elephant')";
In either case one receives an error that the input is not valid syntax.
Upvotes: 2
Views: 104
Reputation: 355
You can use now use ORDER BY CASE with the V4.5CE SQL interface:
CREATE TABLE myTable (
key INTEGER PRIMARY KEY,
animal STRING,
count INTEGER
);
INSERT INTO myTable VALUES(1, 'cat', 4); INSERT INTO myTable VALUES(2, 'dog', 1); INSERT INTO myTable VALUES(3, 'mouse', 6);
SELECT * FROM myTable WHERE count >= 4 ORDER BY CASE animal
WHEN 'mouse' THEN 1
WHEN 'cat' THEN 2
WHEN 'dog' THEN 3
WHEN 'elephant' THEN 4
ELSE 5
END;
-->
key | animal | count
----+--------+------
3 | mouse | 6
1 | cat | 4
Upvotes: 0
Reputation: 156
GridDB's TQL doesn't support ORDER BY CASE but with multi-query you can perform this operation quickly/efficiently.
Please excuse my Python:
queries=[]
queries.append(col.query("select * where count >=4 and animal = 'mouse'"))
queries.append(col.query("select * where count >=4 and animal = 'cat'"))
queries.append(col.query("select * where count >=4 and animal = 'dog'"))
queries.append(col.query("select * where count >=4 and animal = 'elephant'"))
store.fetch_all(queries)
for q in queries:
rs = q.get_row_set()
while rs.has_next():
print(rs.next())
Upvotes: 2