Reputation: 1433
I have an R
code that contains some nested bracket for loop within which I used rmse()
function from Metrics
package. I tried it without the function and it worked, but inside my nested R
code it does not.
Here is what I desire to do with R
2,3,...,48,49
making me have 48 different time series formed from step 1 above.train
and test
sets so I can use rmse
function in Metrics
package to get the Root Mean Squared Error (RMSE) for the 48 subseries formed in step 2.ARIMA
model for each 48 different time series data set.My R code
# simulate arima(1,0,0)
library(forecast)
library(Metrics)
n <- 50
phi <- 0.5
set.seed(1)
wn <- rnorm(n, mean=0, sd=1)
ar1 <- sqrt((wn[1])^2/(1-phi^2))
for(i in 2:n){
ar1[i] <- ar1[i - 1] * phi + wn[i]
}
ts <- ar1
t<-length(ts)# the length of the time series
li <- seq(n-2)+1 # vector of block sizes(i.e to be between 1 and n exclusively)
RMSEblk<-matrix(nrow = 1, ncol = length(li))#vector to store block means
colnames(RMSEblk)<-li
for (b in 1:length(li)){
l<- li[b]# block size
m <- ceiling(t / l) # number of blocks
blk<-split(ts, rep(1:m, each=l, length.out = t)) # divides the series into blocks
singleblock <- vector() #initialize vector to receive result from for loop
for(i in 1:10){
res<-sample(blk, replace=T, 100) # resamples the blocks
res.unlist<-unlist(res, use.names = F) # unlist the bootstrap series
# Split the series into train and test set
train <- head(res.unlist, round(length(res.unlist) * 0.6))
h <- length(res.unlist) - length(train)
test <- tail(res.unlist, h)
# Forecast for train set
model <- auto.arima(train)
future <- forecast(test, model=model,h=h)
nfuture <- as.numeric(out$mean) # makes the `future` object a vector
# use the `rmse` function from `Metrics` package
RMSE <- rmse(test, nn)
singleblock[i] <- RMSE # Assign RMSE value to final result vector element i
}
#singleblock
RMSEblk[b]<-mean(singleblock) #store into matrix
}
RMSEblk
The error I got
#Error in rmse(test, nn): unused argument (nn)
#Traceback:
But when I wrote
library(forecast)
train <- head(ar1, round(length(ar1) * 0.6))
h <- length(ar1) - length(train)
test <- tail(ar1, h)
model <- auto.arima(train)
#forecast <- predict(model, h)
out <- forecast(test, model=model,h=h)
nn <- as.numeric(out$mean)
rmse(test, nn)
It did work
Please point out what I am missing?
Upvotes: 0
Views: 1298
Reputation: 541
Your code does not define nn. Other code that works has nn. To start code with clean slate use this line as first executable line:
rm(list=ls())
Upvotes: 1
Reputation: 506
I am able to run your code after making two very small corrections in your for loop. See the two commented lines:
for (b in 1:length(li)){
l<- li[b]
m <- ceiling(t / l)
blk<-split(ts, rep(1:m, each=l, length.out = t))
singleblock <- vector()
for(i in 1:10){
res<-sample(blk, replace=T, 100)
res.unlist<-unlist(res, use.names = F)
train <- head(res.unlist, round(length(res.unlist) * 0.6))
h <- length(res.unlist) - length(train)
test <- tail(res.unlist, h)
model <- auto.arima(train)
future <- forecast(test, model=model,h=h)
nfuture <- as.numeric(future$mean) # EDITED: `future` instead of `out`
RMSE <- rmse(test, nfuture) # EDITED: `nfuture` instead of `nn`
singleblock[i] <- RMSEi
}
RMSEblk[b]<-mean(singleblock)
}
It is possible that these typos did not result in errors because nn
and out
were defined in the global environment while you ran the for loop. A good debugging tip is to restart R and try to reproduce the problem.
Upvotes: 1