CODEWITHSUNDEEP
pythondjango
Greg Cain
Greg Cain

Reputation: 113

Simple Django program causing me trouble

I've gone through quite a few django tutorials, and I'm finally getting ready to head out on my own. However, my first non-tutorial program is throwing an error, and I've been banging my head for a couple of days. I expect it to be a very noob problem, because, well, I am.

When I use this view

 def todo(request): 
        latest_list = Item.objects.all()
        return HttpResponse(latest_list)

I get

conquer djangocan I do this?learn thislearn this

which are the four items that populate the database. Not very handy since they are concatenated, and they don't appear to be handed off to the template.

When I change my view.py to try to talk to the template using

def todo(request):
        latest_list = Item.objects.all()
        return render_to_response,('index.html', {"latest_list", latest_list})

I get 

'tuple' object has no attribute 'status_code'

Could it be that the model that's returning 'self.task' is limiting the return to only that field? Other tutorial I looked at seemed to return only one value (and returning just 'self' gets me a very similar error.

It could also be that I'm not passing in

Any help that would push me down the correct path would be greatly appreciated.

Greg

My model.py

from django.db import models

class Item(models.Model):
    task = models.CharField(max_length=60)
    taskNotes = models.CharField(max_length=600)
    created = models.DateTimeField(auto_now_add=True)
    done = models.BooleanField(default=False)

    def __unicode__(self):
        return self.task

My views.py

from django.shortcuts import render_to_response, get_object_or_404
from django.template import RequestContext
from django.http import HttpResponse
from myToDo.todo.models import Item

def todo(request): 
    latest_list = Item.objects.all()
    return HttpResponse(latest_list)

My index.html (template)

{% if latest_list %}
    <ul>
    {% for task in latest_list %}
        <li>{{ Item.task }}</li>
    {% endfor %}
    </ul>
{% else %}
    <p>Looks like you're all done</p>
{% endif %}

Upvotes: 1

Views: 2719

Answers (2)

XORcist
XORcist

Reputation: 4367

return render_to_response,('index.html', {"latest_list", latest_list})

Remove that comma affer render_to_response and you should be ok. Reason: the comma makes the return value a tuple object, but need to return an HttpResponse object from a view.

Upvotes: 2

Ignacio Vazquez-Abrams
Ignacio Vazquez-Abrams

Reputation: 799062

You goofed on your return.

def todo(request):
  latest_list = Item.objects.all()
  return render_to_response('index.html', {"latest_list", latest_list})

Note the lack of comma after the function name.

Upvotes: 1

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