I want to name a file with the name of a directory in bash

Question

I'm trying to create files with the name of it's antepenultimate directory:

Example: Directory: a/b/c/d/e/f/g/h/i/j

The name of folder h is different for each case.

So I created an array

array=(/ a / b / c / d / e / f / g / * / * / *)
len=${#array[@]}

for (( q=0; q<$len; q++ ));    
do 
    cd ${array[$q]}
    sleep 1
    mri_convert 0001*.dcm RAW.nii.gz #--->this line is just converting the format of file 0001*.dcm in to file RAW.nii.gz
done

This code is working but I want the file RAW.nii.gz to be named h_RAW.nii.gz

I tried doing this:

s1="${array%/*/*}"
$ echo "${s1##*/}"

and then:

mri_convert 0001*.dcm ${s1##*/}_RAW.nii.gz

but it's not working.

Answer 1

Let's see if I can help. I'm not exactly sure of the details of what you're trying to do (mainly because the code you posted:

for (( q=0; q do cd ${array[$q]} sleep 1 mri_convert 0001*.dcm RAW.nii.gz

is not syntactically correct. So, that can't be what you're actually doing.

Just a hint of how i would approach a problem like this:

for path6 in /a/b/c/*/*/*
do
    path5="${path6##*/}"
    path4="${path5##*/}"
    name4="${path4%/*}"
    echo "Processing ${path4}"
    mriconvert "${path6}"/0001*.dcm "${path6}/${name4}_RAW.nii.gz"
done

Answer 2

How about

cd /a/b/c/d/e/f/g
for dir in *; do
    [[ -d $dir ]] || continue
    for subdir in "$dir"/*/*/; do (
        # doing this in a subshell so we don't need to "undo" this cd
        cd "$subdir"
        mri_convert 0001*.dcm "${dir}_RAW.nii.gz"
    ); done
done