CODEWITHSUNDEEP
javaregex
John
John

Reputation: 336

regex to remove data between "some text (some text)"?

I have a string in java which contains text as 

Hello user your choice is in (1,2,3,4) as selected by you.

Now I want to remove choice is in (1,2,3,4) from this string with "".

I cannot directly do it using replace() in java as data inside the () is dynamic and changes every time.

Output required

Hello user your as selected by you.

I tried using regex but it failed and did not work, my regex

(?s)(\\choice is in .*?\\\\(\\\\)

Upvotes: 1

Views: 126

Answers (4)

Arvind Kumar Avinash
Arvind Kumar Avinash

Reputation: 79245

Given below is a non-regex solution:

public class Main {
    public static void main(String[] args) {
        String s = "Hello user your choice is in (1,2,3,4) as selected by you.";
        int start = s.indexOf(" choice is in (");
        int end = s.indexOf(")", start);// Index of `)` after the index, `start`
        s = s.substring(0, start) + s.substring(end + 1);
        System.out.println(s);
    }
}

Output:

Hello user your as selected by you.

Upvotes: 2

Smit
Smit

Reputation: 11

Please refer below code.

    String pattern = "choice is in (.*?) ";

    String userString = "Hello user your choice is in (1,2,3,4) as selected by you";
    userString = userString.replaceAll(pattern, "");
    System.out.println(userString);

Output will be : Hello user your as selected by you

Upvotes: 1

Majid Roustaei
Majid Roustaei

Reputation: 1764

Try This:

    String pattern = "choice is in (.*) as";

    String userString = "Hello user your choice is in (1,2,3,4) as selected by you";
    userString = userString.replaceAll(pattern, "as");
    System.out.println(userString);

And the output would be:

Hello user your as selected by you

Upvotes: -1

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 627056

You may use

.replaceAll("\\s+choice\\s+is\\s+in\\s+\\([^()]*\\)", "")

See the regex demo.

  • \s+ - 1+ whitespaces
  • choice\s+is\s+in - choice is in with any 1+ whitespaces in between words
  • \s+ - 1+ whitespaces
  • \([^()]*\) - a (, then any 0+ chars other than ( and ) and then a )

See Java demo:

String s = "Hello user your choice is in (1,2,3,4) as selected by you.";
System.out.println(s.replaceAll("\\s+choice\\s+is\\s+in\\s+\\([^()]*\\)", ""));
// => Hello user your as selected by you.

Upvotes: 2

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