Reputation: 33
I'm trying to overload the "<<" operator in order to print a class that has been declared inside a template class. I've looked for a solution but I haven't really found any examples similar to my own. The following code illustrates my problem:
#include <iostream>
template<class T>
class main_class
{
public:
class dependent_class
{
public:
dependent_class() : val(0) { }
template<class T>
friend std::ostream& operator<<(std::ostream&, const dependent_class&);
protected:
int val;
};
};
template<class T>
std::ostream& operator<<(std::ostream& out, const typename main_class<T>::dependent_class& v)
{
return out << v.val;
}
int main(int argc, char* argv[])
{
main_class<int>::dependent_class v;
std::cout << v; // error: no operator "<<" matches these operands
// operand types are: std::ostream << main_class<int>::dependent_class
return 0;
}
Upvotes: 3
Views: 210
Reputation: 4899
Move the definition of operator<<
to the scope of dependent_class
and remove template<class T>
before the declaration:
#include <iostream>
template<class T>
class main_class
{
public:
class dependent_class
{
public:
dependent_class() : val(0) { }
friend std::ostream& operator<<(std::ostream& out, const dependent_class& v)
{
return out << v.val;
}
protected:
int val;
};
};
int main(int argc, char* argv[])
{
main_class<int>::dependent_class v;
std::cout << v; // error: no operator "<<" matches these operands
// operand types are: std::ostream << main_class<int>::dependent_class
return 0;
}
Upvotes: 0
Reputation:
#include <iostream>
template<class T>
class main_class
{
public:
class dependent_class
{
public:
dependent_class() : val(0) { }
friend std::ostream& operator<<(std::ostream& out, const main_class<T>::dependent_class& v){
return out << v.val;
}
protected:
int val;
};
};
int main(int argc, char* argv[])
{
main_class<int>::dependent_class v;
std::cout << v; // error: no operator "<<" matches these operands
// operand types are: std::ostream << main_class<int>::dependent_class
return 0;
}
You were having errors in your code.
In the dependent_class you are using the template twice which shadows the template parameter.
class dependent_class
{
public:
dependent_class() : val(0) { }
template<class T> //here
friend std::ostream& operator<<(std::ostream&, const dependent_class&);
protected:
int val;
};
Upvotes: 1