CODEWITHSUNDEEP
xqueryexist-db
Ihe Onwuka
Ihe Onwuka

Reputation: 477

Cannot wrap element around XQuery output

Returning to XQuery after a long hiatus.

let $root := <a:b xmlns:a="ans" xmlns:c="cns"/>
     for $prefix in in-scope-prefixes($root)[not(. = ('xml', 'xsi'))]
      return 
          namespace-uri-for-prefix($prefix,$root) ! 
              <param name="{$prefix}" value="{.}"/>

gives the expected

<param name="a" value="ans"/>  
<param name="c" value="cns"/>

But if I try to wrap an element around that output like below nothing is returned

<parameters>{
let $root := <a:b xmlns:a="ans" xmlns:c="cns"/>
     for $prefix in in-scope-prefixes($root)[not(. = ('xml', 'xsi'))]
      return 
          namespace-uri-for-prefix($prefix,$root) ! 
              <param name="{$prefix}" value="{.}"/>
}</parameters>

So what is wrong and how do I wrap the output in a parameters element?

Upvotes: 1

Views: 139

Answers (1)

Mads Hansen
Mads Hansen

Reputation: 66723

Try letting a variable with the sequence of <param> elements, and return the <parameters> element referencing that variable instead of putting the FLWOR inline.

You shouldn't have to do that. I was able to generate the desired output in MarkLogic with your original code, but it seems necessary for eXist to generate the desired output.

xquery version "3.0" encoding "UTF-8";
let $root := <a:b xmlns:a="ans" xmlns:c="cns"></a:b>
let $params :=
     for $prefix in in-scope-prefixes($root)[not(. = ('xml', 'xsi'))]
     return 
       namespace-uri-for-prefix($prefix,$root) ! 
              <param name="{$prefix}" value="{.}"/>
return 
  <parameters>{ $params }</parameters>

Upvotes: 3

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