CODEWITHSUNDEEP
javascriptgenerator
Andrew
Andrew

Reputation: 795

generate yield for every item in array Generator JS

I'm trying to make my generator more flexible

From this:

function *formValidationSequence () {
    yield someRef.current.func()
    yield someOtherRef.current.func()
    ...
}

To this:

const array = [someRef, someOtherRef]

const handler = (array) => {
    const sequence = testSequence(function *() {
        yield* array.map(item => item.current.func())
    })
}

But it doesn't work. I want to create yield dynamically for every ref/item in an array, without to call 'em instantly.

How it should be done?

Upvotes: 2

Views: 1228

Answers (2)

Jonas Wilms
Jonas Wilms

Reputation: 138267

You do

 yield* iterable

which will create an iterator from the iterable and yield all it's values up. Now your iterable is the thing returned from .map, which is an array that already contains all the calculated results. To yield every item one after another, you need a for loop, as that can be interrupted:

 for(const item of [someRef, someOtherRef])
   yield* item.current.func();

Upvotes: 3

Aplet123
Aplet123

Reputation: 35512

map will execute the function on every item in the array before calling yield* on it. If you want to only call one function per iteration, then just use a regular loop:

function*() {
    for (const el of array) {
        yield el.current.func();
    }
}

Upvotes: 1

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