CODEWITHSUNDEEP
pythonloops
vnikonov_63
vnikonov_63

Reputation: 191

Problem with iterating over the list of lists

I am trying to compute a transpose of the matrix, which I have in the form of list of lists. The initial matrix is mn, I have created a matrix nm. The problem appears when I start to use the nested loop. 

m = 0
for i in range(0, rows):
    for j in range(0, columns):
        final1[j][i] = m
        print(final1)
        m += 1

I deliberately print the whole list of lists (final) to see how at each step my values are changing, also I just assign consequent natural numbers for simplicity. what I see is (first 4 lines of the output)

[[0, None, None, None], [0, None, None, None], [0, None, None, None]]
[[1, None, None, None], [1, None, None, None], [1, None, None, None]]
[[2, None, None, None], [2, None, None, None], [2, None, None, None]]
[[2, 3, None, None], [2, 3, None, None], [2, 3, None, None]]

So, by accessing final[j][i], at position j = 0, i = 0 the values final[1][0] and final[2][0] are also changing. How to avoid this? and make the first 4 lines of this format:

[[0, None, None, None], [None, None, None, None], [None, None, None, None]]
[[0, None, None, None], [1, None, None, None], [None, None, None, None]]
[[0, None, None, None], [1, None, None, None], [2, None, None, None]]
[[0, 3, None, None], [1, None, None, None], [2, None, None, None]]

rows = int(input())
columns = int(input())
final1 = [[None] * rows] * columns

This is the way I declare final1

Upvotes: 0

Views: 62

Answers (2)

San
San

Reputation: 463

This happens because the declaration statement is internally equivalent to appending a single list ([None]*rows) column times into the final1 list.

If you are familiar with copy problem , this is nearly the same. All the lists inside final1 are the same lists in terms of the memory they represent.

That's why when you update a value in one list, it gets reflected to all.

Note : You are actually creating a list of lists with column number of rows and row number of columns.

You can solve this issue by declaring final1 this way :

final1 = [[None for i in range(rows)] for j in range(columns)]

p.s: I've used rows inside and columns outside just to make it as an alternative to your declaration. It still produces a list of lists with column number of rows and row number of columns

Upvotes: 2

BluePigeon
BluePigeon

Reputation: 1812

This works:

rows = int(input())
columns = int(input())
final1 = [[None for i in range(rows)] for j in range(columns)]

m = 0
for i in range(rows):
    for j in range(columns):
        final1[j][i] = m
        m += 1

print(final1)

Upvotes: 1

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