Reputation: 4130
I have a servlet which is meant to handle the upload of a very large file. I am trying to use commons fileupload to handle it. Currently, the file I am attempting to upload is 287MB.
I set up the FileItemFactory and ServletFileUpload, then set a very large max file size on the ServletFileUpload.
Unfortunately, when I attempt to create a FileItemIterator, nothing happens. The form is set with the correct action, multipart encoding, and for the POST method.
Can anyone assist? doPost() of the servlet is posted below:
@Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
// ensure that the form is multipart encoded since we are uploading a file
if (!ServletFileUpload.isMultipartContent(req)) {
//throw new FileUploadException("Request was not multipart");
log.debug("Request was not multipart. Returning from call");
}
// create a list to hold all of the files
List<File> fileList = new ArrayList<File>();
try {
// setup the factories and file upload stuff
FileItemFactory factory = new DiskFileItemFactory();
ServletFileUpload upload = new ServletFileUpload(factory);
upload.setFileSizeMax(999999999);
// create a file item iterator to cycle through all of the files in the req. There SHOULD only be one, though
FileItemIterator iterator = upload.getItemIterator(req);
// iterate through the file items and create a file item stream to output the file
while (iterator.hasNext()) {
// get the file item stream from the iterator
FileItemStream fileItemStream = iterator.next();
// Use the Special InputStream type, passing it the stream and the length of the file
InputStream inputStream = new UploadProgressInputStream(fileItemStream.openStream(), req.getContentLength());
// create a File from the file name
String fileName = fileItemStream.getName(); // this only returns the filename, not the full path
File file = new File(tempDirectory, fileName);
// add the file to the list
fileList.add(file);
// Use commons-io Streams to copy from the inputstrea to a brand-new file
Streams.copy(inputStream, new FileOutputStream(file), true);
// close the inputstream
inputStream.close();
}
} catch (FileUploadException e) {
e.printStackTrace();
}
// now that we've save the file, we can process it.
if (fileList.size() == 0) {
log.debug("No File in the file list. returning.");
return;
}
for (File file : fileList) {
String fileName = file.getName();
BufferedReader reader = new BufferedReader(new FileReader(fileName));
String line = reader.readLine();
List<Feature> featureList = new ArrayList<Feature>(); // arraylist may not be the best choice since I don't know how many features I'm importing
while (!line.isEmpty()) {
String[] splitLine = line.split("|");
Feature feature = new Feature();
feature.setId(Integer.parseInt(splitLine[0]));
feature.setName(splitLine[1]);
feature.setFeatureClass(splitLine[2]);
feature.setLat(Double.parseDouble(splitLine[9]));
feature.setLng(Double.parseDouble(splitLine[10]));
featureList.add(feature);
line = reader.readLine();
}
file.delete(); // todo: check this to ensure it won't blow up the code since we're iterating in a for each
reader.close(); // todo: need this in a finally block somewhere to ensure this always happens.
try {
featureService.persistList(featureList);
} catch (ServiceException e) {
log.debug("Caught Service Exception in FeatureUploadService.", e);
}
}
}
Upvotes: 1
Views: 5525
Reputation: 4130
It was an incredibly stupid problem. I left the name attribute off of the FileUpload entry in the GWT UiBinder. Thanks for all of the help from everyone.
Upvotes: 2
Reputation: 64690
Are the only request parameters available File items? Because you may want to put in a check:
if (!fileItemStream.isFormField()){
// then process as file
otherwise you'll get errors. On the surface of things your code looks fine: no errors in the Tomcat logs?
Upvotes: 0