CODEWITHSUNDEEP
pythonregexstring
Claire Gribbin
Claire Gribbin

Reputation: 33

How to match up to double closing curly braces not followed with a curly brace

So, I have a RegEX equation and line of code that removes all curly braces from a string, but I want it to only remove the brackets when they are balanced

here is my line:

matches = re.findall(r'{{(.*?)}}', url)

string example: {{location.city}} output: location.city

But let's say the input string is:

{{location.city}}}}

I want the output to be location.city}}

I've been messing around with RegEx for a while and still haven't figured out how to do it.

Upvotes: 1

Views: 537

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626961

You may require no } after the closing }}:

re.findall(r'{{(.*?)}}(?!})', url)

See the regex demo

The (?!}) is a negative lookahead that fails the match if there is a } immediately on the right.

If the same is required with {{, if there can be no { before the {{ at the start, add a lookbehind:

re.findall(r'(?<!{){{(.*?)}}(?!})', url)

See this regex demo.

Upvotes: 2

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