CODEWITHSUNDEEP
python
William
William

Reputation: 81

Unpacking a lists of list, into individual lists using another list

Problem:
I have a List of lists (lists_of_lists), that each contain 5 floats in each list. I am trying to unpack lists_of_lists and for every unpacked list, name it using the values in my country_list

Example of desired output:

Brazil = [28.42, 56.12, 59.97, 61.69, 60.34]
British = [39.1, 57.96, 56.29, 56.5, 71.25]
Note: the ordering in both lists correspond, as demonstrated above.

Resources:

list_of_lists = [[28.42, 56.12, 59.97, 61.69, 60.34], [39.1, 57.96, 56.29, 56.5, 71.25], [14.3, 42.33, 58.54, 41.24, 49.76]]

country_list = ['brazil', 'british', 'cantopop', 'mandopop', 'french', 'german', 'indian', 'iranian', 'malay', 'philippines-opm', 'spanish', 'swedish', 'turkish']

My thinking: is that I should use a for loop to iterate through the country_list and for every string (country name), create a new list and populate using the same positioned list in the list_of_lists

Any hints would be great. Thank you

Upvotes: 0

Views: 43

Answers (4)

InstaK0
InstaK0

Reputation: 362

I would create a dict to store the results.

myDict = {}
for i in range(len(list_of_lists)):
    myDict[country_list(i)] = list_of_lists(i)

Upvotes: 0

kuco 23
kuco 23

Reputation: 830

dict(zip(country_list, list_of_lists))

will give you a dictionary of country: list, as

{'brazil': [28.42, 56.12, 59.97, 61.69, 60.34], 'british': [39.1, 57.96, 56.29, 56.5, 71.25], 'cantopop': [14.3, 42.33, 58.54, 41.24, 49.76]}

As you can see the shortest element zipped is used (here country_list).

Upvotes: 3

Patrick Artner
Patrick Artner

Reputation: 51643

Creating "named" variables makes no sense. Put them into a dictionary:

list_of_lists= [[28.42, 56.12, 59.97, 61.69, 60.34], 
                [39.1, 57.96, 56.29, 56.5, 71.25], 
                [14.3, 42.33, 58.54, 41.24, 49.76]]

country_list = ['brazil', 'british', 'cantopop', 'mandopop', 'french',
                'german', 'indian', 'iranian', 'malay', 'philippines-opm',
                'spanish', 'swedish', 'turkish']

merger = {k:v for k,v in zip( country_list, list_of_lists)}

print(merger)

Output:

{'brazil': [28.42, 56.12, 59.97, 61.69, 60.34], 
 'british': [39.1, 57.96, 56.29, 56.5, 71.25], 
 'cantopop': [14.3, 42.33, 58.54, 41.24, 49.76]}

Shortest list wins. You can use the dictionary, to get all of brazils values:

print(merger["brazil"])    # [28.42, 56.12, 59.97, 61.69, 60.34]

To get all values iterate the dict:

for key in merger:
    print(key)
    print(merger[key])

Output:

brazil
[28.42, 56.12, 59.97, 61.69, 60.34]
british
[39.1, 57.96, 56.29, 56.5, 71.25]
cantopop
[14.3, 42.33, 58.54, 41.24, 49.76]

See:

Upvotes: 0

Vahid
Vahid

Reputation: 1417

enumerate gives you iterator for both index and value

list_of_lists= [[28.42, 56.12, 59.97, 61.69, 60.34], [39.1, 57.96, 56.29, 56.5, 71.25], [14.3, 42.33, 58.54, 41.24, 49.76]]

country_list = ['brazil', 'british', 'cantopop']

# to print
for idx, country in enumerate(country_list):
    print(country, list_of_lists[idx])

# to store in a dictionary:
d = dict((country, list_of_lists[idx]) for idx, country in enumerate(country_list))

Upvotes: 0

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