CODEWITHSUNDEEP
pythonregex
pylearner
pylearner

Reputation: 1460

Discard floating numbers from string list

am trying to ignore a float value from a string and filing to do so.

string = ['20', '30', '40', '.50', '0.60', 'OA', '2A']

code :

match = []
for i in string:
     if re.match('(?<![\.\d])[0-9]+(?![\.\d])', i):
              match.append(i)
print(match)

output : ['20', '30', '40']

This code is ignoring two elements as they are not numerical 'OA', '2A'

expected output:

['20', '30', '40', 'OA', '2A']

Upvotes: 0

Views: 55

Answers (1)

Jan
Jan

Reputation: 43169

You could use

import re

lst = ['20', '30', '40', '.50', '0.60', 'OA', '2A']

pattern = re.compile(r'-?\d*\.\d+$')

output = [item for item in lst if not pattern.match(item)]
print(output)

This yields

['20', '30', '40', 'OA', '2A']

re.match() implicitely adds an anchor in the beginning, so the actual pattern is

^-?\d*\.\d+$

As @Wiktor points out, Python 3.x has re.fullmatch(), so you could use

pattern = re.compile(r'-?\d*\.\d+')
output = [item for item in lst if not pattern.fullmatch(item)]

See a demo on regex101.com.

Upvotes: 1

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