CODEWITHSUNDEEP
pythonnumpy-ndarray
Quintium
Quintium

Reputation: 368

Why does this line cause a boolean error?

len([True for i in a if any([any(j == b[:, 0]) for j in i])])

This is my line of code. a is a multidimensional list and b is a nd.array. When I run it, it returns this error:

The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()

Even though I used any() at every place that is needed. Where's my mistake?

Edit: Values for the lists:

  1. a = [[[[0, 0], [0, 0]]]]
  2. b = np.array([[[[0, 0], [0, 0]], 0]])

Upvotes: 0

Views: 90

Answers (1)

rpoleski
rpoleski

Reputation: 998

The problem is produced by:

any(j == b[:, 0])

use:

(j == b[:, 0]).any()

instead. Same for the outer any(). Note that any() can take an iterable, which np_array.any() is a function from numpy.

Upvotes: 2

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