CODEWITHSUNDEEP
javacommand-linesystem-properties
Alexander Porter
Alexander Porter

Reputation: 43

Can I get the path of the currently running java executable?

Suppose I want to run a java program from the command line and I use this command:

myExes\java\java.exe AJavaProgram

As you can see, java.exe is not in my path, so I am running it manually rather than simply using the command java AJavaProgram.

I would like the program to return/print the first entry in the command, in this case, that entry is myExes\java. (Including java.exe at the end of this is also fine).

Is there a way to do this?

Initially, I thought it would be simple. args[0] would return the path, but that is not the case.

Upvotes: 4

Views: 4117

Answers (4)

VGR
VGR

Reputation: 44413

ProcessHandle.current() returns the current Java process. You can use that to see the full command in the process handle’s info:

ProcessHandle.current().info().command().ifPresent(
    cmd -> System.out.println(cmd));

Upvotes: 9

stackguy
stackguy

Reputation: 190

When you do myExes\java\java.exe AJavaProgram AJavaProgram is the arg to java.exe and not the reverse. Its the same when you do java AJavaProgram, AJavaProgram is the arg to java.

Upvotes: -2

Andreas
Andreas

Reputation: 159250

You can't get the string "myExes\java\java.exe", but you can get the location of the Java installation.

The following are results for running with OpenJDK 14 on Windows 10:

System.out.println(System.getProperty("java.home"));
System.out.println(System.getProperty("sun.boot.library.path"));

Output

C:\prog\Java64\jdk-14
C:\prog\Java64\jdk-14\bin

For reference, the full path of java.exe is:

C:\prog\Java64\jdk-14\bin\java.exe

Upvotes: 2

yeahseol
yeahseol

Reputation: 385

How about this way?
You can get a java home dir.

String path = System.getProperty("java.home");

Upvotes: -2

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