CODEWITHSUNDEEP
pythonregexstringfindandmodify
Prab
Prab

Reputation: 504

find words that matches the 3 consecutive vowels Regex

text = "Life is beautiful"
pattern = r"[aeiou]{3,}"
result = re.findall(pattern, text)
print(result)

desired result: ['beautiful']

the output I get: ['eau']

I have tried googling and etc....I found multiple answers but none of them worked!! I am new to regex so maybe I am having issues but I am not sure how to get this to out

I have tried using r"\b[abcde]{3,}\b" still nothing SO please help!!

Upvotes: 4

Views: 2971

Answers (5)

Justin Shams
Justin Shams

Reputation: 11

The first part of the regex looks for all letters, upper or lower case (as well as numbers and underscores which is not necessary), but for the purpose of this question it works. We just need to find characters leading up to a word with (at least) three vowels in a row. Then we finish it off by looking for lowercase letters at the tail end of the word if any remain.

pattern = r"[\w]+[aeiou]{3,}[a-z]+"

Upvotes: 1

Zac
Zac

Reputation: 1

I know it's a late reply but just wanted to share this for whoever searches this up!

Answer: pattern = r"\b[a-zA-Z][aeiou]{3,}[a-z]\b" OR experimenting with [\w]* instead of [a-zA-Z]

change the first match from [a-z] to [a-zA-Z]

Upvotes: 0

Mustafa Aliraqi
Mustafa Aliraqi

Reputation: 1

pattern=r"\b\w*[aeiou]{3,}\w*\b"

\w* For any alpha Alphanumerics that "could" exist before and after the vowels

Upvotes: 0

gzoanetti
gzoanetti

Reputation: 1

A little improvement on the former solution would be using \w instead a-z as the character classes (This will match lower and uppercase letters)

\b[\w]+[aeiou]{3,}[\w]+\b

Cheers!

Upvotes: 0

Nick
Nick

Reputation: 147266

Your regex only captures the 3 consecutive vowels, so you need to expand it to capture the rest of the word. This can be done by looking for a sequence of letters between two word breaks and using a positive lookahead for 3 consecutive vowels within the sequence. For example:

import re

text = "Life is beautiful"
pattern = r"\b(?=[a-z]*[aeiou]{3})[a-z]+\b"
result = re.findall(pattern, text, re.I)
print(result)

Output:

['beautiful']

Upvotes: 4

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