CODEWITHSUNDEEP
python
Affaxerd
Affaxerd

Reputation: 39

i want to write a python code that calculates time

If I leave my house at 6:52 am and run 1 mile at an easy pace (8:15 per mile), then 3 miles at tempo (7:12 per mile) and 1 mile at easy pace again, what time do I get home for breakfast?

This is what I have tried:

>>> import datetime
>>> t=datetime.time(6,52)
>>> print (t)
06:52:00
>>> b=t+datetime.timedelta (8 hours,15 minutes)
  File "<stdin>", line 1
    b=t+datetime.timedelta (8 hours,15 minutes)
                              ^
SyntaxError: invalid syntax
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Upvotes: 0

Views: 457

Answers (1)

notacorn
notacorn

Reputation: 4079

So let's walk it back a few steps. When you tried b=t+datetime.timedelta (8 hours,15 minutes), what you were trying to do was increment your time object by 8 minutes and 15 seconds, using the timedelta function. In Python, functions take arguments, and timedelta, like any other function, has specific kinds of values you can pass for arguments. You can find them here, because since datetime is a library, it has nice documentation for everything. It looks like you were using IDLE which also gives you a peek at type hints:

enter image description here

So now we know that timedelta takes any one of days=0, seconds=0, microseconds=0, milliseconds=0, minutes=0, hours=0, weeks=0.

In our case, we want to add 8 minutes and 15 seconds to our original datetime object.

That would mean setting minutes=8 and seconds=15.

So when we call the timedelta function, to avoid that syntax error, we want to invoke the function like such:

b=t+datetime.timedelta(minutes=8, seconds=15)

And there you have it! Just remember what is and is not valid syntax in Python. Python doesn't know a thing about what you mean when you give it plain English.

Upvotes: 3

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