CODEWITHSUNDEEP
shellvariablesunixscripting
saik
saik

Reputation: 31

How to pass variable name from a file and use that variable in script in unix

I have a config file in unix as

Variable_name:sequences:Status
ABC:1234:/path/txt

and I have a script in unix as

$ABC="select * from table"

I want to pass the variable name from file and use the variable in script with the value in script.

so I need to run script like

for i in /path/file_config;
 $Variable=ABC
 echo $variable # need result "select* from table"

Please help me in this

Upvotes: 0

Views: 497

Answers (2)

Parthiban Sekar
Parthiban Sekar

Reputation: 49

Adding a slight improvement to Shawn's response above:

for Variable_name in `awk -F: '{ print $1 }' /path/file_config`; do
Variable=$Variable_name
echo ${!Variable}
done

Upvotes: 0

Shawn
Shawn

Reputation: 52336

In bash (But not other shells), ${!foo} is an indirect reference that expands to the value of the variable named in $foo.

So,

ABC="select * from table"
name=ABC
echo "${!name}"

will display select * from table

Upvotes: 1

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