CODEWITHSUNDEEP
javastringcompare
chuck finley
chuck finley

Reputation: 459

Compare two strings of ints in java

I have two Strings that contain numbers and I want to see if the second string contains the same numbers as the first String, whether they are in order or not. If it has any number repeating than report false. Is there anyway in java other than using .charAt() because its not working for number after 10? 

String one = "1 2 3 4 5 "; 
String two = " 3 2 1 4 5 ";
String three = "3 2 1 4 4 ";

Upvotes: 5

Views: 4330

Answers (8)

Naveed
Naveed

Reputation: 42143

Looks like homework. So these steps you can follow:

  • Trim both strings
  • Convert both strings into ArrayList using space separator
  • Sort both arrays numerically
  • Compare both arrays

Upvotes: 7

Jiří Šitina
Jiří Šitina

Reputation: 306

I would at first parse numbers as integers, put them to the set and compare them: 

  import java.util.SortedSet;
import java.util.StringTokenizer;
import java.util.TreeSet;


public class StringsCompare {

    private static String one = "1 2 3 4 5 6"; 
    private static String two = " 3 2 1 5 6 4 ";

    public static void main(String[] args) {
        StringsCompare sc = new StringsCompare();

        System.out.println(sc.compare(one, two));
    }

    private boolean compare(String one, String two) {

        SortedSet<Integer> setOne = getSet(one);    
        SortedSet<Integer> setTwo = getSet(two);

        return setOne.equals(setTwo);
    }

    private SortedSet<Integer> getSet(String str) {
        SortedSet<Integer> result = new TreeSet<Integer>();

        StringTokenizer st = new StringTokenizer(str, " ");

        while (st.hasMoreTokens()) {
            result.add(Integer.valueOf(st.nextToken()));
        }

        return result;
    }
}

Upvotes: 0

Prince John Wesley
Prince John Wesley

Reputation: 63708

Try like this.

String one = "1 2 3  4 5 ";
String two = " 3 2 1 4 5 ";
Set<String> a = new HashSet<String> (Arrays.asList(one.trim().replaceAll("\\s*"," ").split(" ")));
Set<String> b = new HashSet<String> (Arrays.asList(two.trim().replaceAll("\\s*"," ").split(" ")));
boolean ret = (a.size() == b.size()) && a.containsAll(b);

Upvotes: 2

Oliver Charlesworth
Oliver Charlesworth

Reputation: 272802

I would not perform the comparison on the raw strings. Instead, first convert each String to a List<Integer> using String.split() and Integer.parseInt() on each result. Then sort() the lists into ascending order, and then it becomes very easy to compare them.

Upvotes: 2

MAK
MAK

Reputation: 26586

You split the strings on whitespace (using either String.split or StringTokenizer) and then convert each of the tokens into a number. Place all the numbers in string one into a HashSet. Do the same for string two. Now all you have to do is to check whether each entry in the first HashSet also occurs in the second one.

Upvotes: 0

Denis Tulskiy
Denis Tulskiy

Reputation: 19187

You can use Scanner.nextInt() to read numbers from the string, add them to a Set, and see if set1.equals(set2) is true.

Upvotes: 4

f1dave
f1dave

Reputation: 1297

You could tokenize/split the strings based on the spaces, then loop through the resulting tokens which would be the numbers themselves.

Upvotes: 0

patapizza
patapizza

Reputation: 2398

Try to parse the strings in int.

Integer.parseInt(One).intValue() == Integer.parseInt(two).intValue()

I'm not sure what you're trying to do but my guess is that you'd better to use arrays.

Upvotes: -1

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