CODEWITHSUNDEEP
pythonpython-3.xstringlist
Benn
Benn

Reputation: 189

Python compare part of string to list

I have multiple strings that looks like this:

“BPBA-SG790-NGTP-W-AU-BUN-3Y”

I want to compare the string to my list and if part of the string is in the list, I want to get only the part that is found on the list as a new variable.

This is my code:

    mylist = ["770", "790", "1470", "1490"]
    sq = “BPBA-SG790-NGTP-W-AU-BUN-3Y”

    matching = [s for s in mylist if any(xs in s for xs in sq)]
    print(matching)

>>> ['770', '790', '1470', '1490']

For example this is what I want to get:

    mylist = ["770", "790", "1470", "1490"]
    sq = “BPBA-SG790-NGTP-W-AU-BUN-3Y”

    matching = [s for s in mylist if any(xs in s for xs in sq)]
    print(matching)

>>> 790

Any idea how to do this?

Upvotes: 0

Views: 1305

Answers (5)

chash
chash

Reputation: 4423

[s for s in mylist if s in sq]

For those who dislike brevity:

This is a list comprehension. It evaluates to a list of strings s in mylist that satisfy the predicate s in sq (i.e., s is a substring of sq).

Upvotes: 0

bro
bro

Reputation: 165

try

mylist = ["770", "790", "1470", "1490"]
sq = "BPBA-SG790-NGTP-W-AU-BUN-3Y"

b = [x for x in mylist if sq.find(x) != -1]
print b

Upvotes: 1

Eeshaan
Eeshaan

Reputation: 1635

Not sure I get your question, but the following should do the trick

[x for x in mylist if x in sq]

It return you with a list of those elements of the list that appears in the string

Upvotes: 1

Harka
Harka

Reputation: 36

You can use the in keyword from python:

mylist = ["770", "790", "1470", "1490"]
sq = "BPBA-SG790-NGTP-W-AU-BUN-3Y"
for i in mylist:
    if i in sq:
        print(i)

The code iterates through the list and prints the list element if it is in the string

Upvotes: 2

Red
Red

Reputation: 27547

Like this, you can use a list comprehension:

mylist = ["770", "790", "1470", "1490"]
sq = "BPBA-SG790-NGTP-W-AU-BUN-3Y"

matching = [m for m in mylist if m in sq]

print(matching)

Output:

['790']

Upvotes: 3

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