CODEWITHSUNDEEP
phpjavascript
steve
steve

Reputation: 879

PHP variable in Javascript

Consider this simple example;

<?php $text = test; ?>

<script type="text/javascript" defer="defer">

var test;

test = "<?php echo $text; ?>"

$(document).ready(function(){
alert(test);
});

</script>

This works fine. Creating the alert with the text from the php var. However, if I place; 

<?php $text = test; ?>

below the script - it does not work. I've tried the defer function. What am I doing wrong?

Cheers

Upvotes: 1

Views: 276

Answers (3)

James
James

Reputation: 22246

There are two computers involved, the web server (which processes php) and the user's browser (which processes javascript). So no, you cannot transfer a javascript variable back to php without sending the value of that variable from the user's browser to the web server (normally done by posting a form or ajax).

Upvotes: 0

user743234
user743234

Reputation:

Seems like you are trying to assign a client-side variable to a server-side variable?

Due to my knowledge, server-side variables can NOT "interact" directly with client-sider variables without anything in between. This means <?php $test = test; ?> doesn't work properly since variables that are included in <?php ?> will be treated as server-side variables, and thus, your client-side variable test is either considered as

  • an undefined constant, or
  • a string without quotes ''

Upvotes: 1

Scott Harwell
Scott Harwell

Reputation: 7465

If you place 

  <?php $text = "test"; ?>

below the JS code, the the variable $text is not defined yet, so you cannot echo it earlier (edit) in the script.

Upvotes: 6

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