CODEWITHSUNDEEP
python-3.xparameter-passinginit
Akshaya V
Akshaya V

Reputation: 5

Overwriting init() in python. TypeError: __init__() takes 1 positional argument but 3 were given

class A:
    x = 0

    def __init__(self, a, b):
        self.a = a
        self.b = b
        A.x += 1

    def __init__(self):
        A.x += 1

    def displayCount(self):
        print('Count : %d' % A.x)

    def display(self):
        print('a :', self.a, ' b :', self.b)

a1 = A('George', 25000)
a2 = A('John', 30000)
a3 = A()
a1.display()
a2.display()
print(A.x)

I expect output as:

a : George b : 25000

a : John b : 30000

3

But I'm getting this error:

TypeError: init() takes 1 positional argument but 3 were given

Help out a beginner

Thanks.

Upvotes: 0

Views: 857

Answers (1)

ruohola
ruohola

Reputation: 24038

You can't have overloaded methods in a Python class.

This will result in just the second __init__ staying around and the first one will be discarded:

def __init__(self, a, b):  # Will get shadowed and thrown away.
    self.a = a
    self.b = b
    A.x += 1

def __init__(self):  # Only this one will be left in the class.
    A.x += 1

You can achieve pretty much the same functionality with parameter defaults:

def __init__(self, a=None, b=None):
    self.a = a
    self.b = b
    A.x += 1

Upvotes: 1

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