VividMan
VividMan

Reputation: 1

Where is the Object class or java.lang imported into the scala package or Any class?

From my understanding the ultimate class in Scala is Any class. However, I thought Scala built of the Java, so would not the ultimate class be Object? I have been checking the documentation and I could be wrong but it does not show that Object is the parent class of Any nor can I see anywhere the java.lang package being imported into Scala, which should be its backbone right?

Upvotes: 0

Views: 117

Answers (2)

Jörg W Mittag
Jörg W Mittag

Reputation: 369546

You are confusing the Scala Programming Language with one of its Implementations.

A Programming Language is a set of mathematical rules and restrictions. Not more. It isn't "written in anything" (except maybe in English) and it isn't "built off anything" (except maybe the paper that the specification is written on).

An Implementation is a piece of software that either reads a program written in the Programming Language and executes that program in such a way that the exact things that the Programming Language Specification say should happen, do happen (in which case we call the Implementation an Interpreter), or it reads the program and outputs another program in another language in such a way that executing that output program with an interpreter for its language makes things happen in exactly the way that the Specification for the input language says.

Either way, it is the job of the person writing the Implementation to make sure that his Implementation does what the Specification says it should do.

So, even if I am writing an Implementation of Scala that is "built off Java" and written in Java, I still need to make sure that Any is the top type, because that's what the Scala Language Specification says. It is probably instructive to look at how, exactly, the Scala Language Specification phrases this [bold emphasis mine]:

Classes AnyRef and AnyVal are required to provide only the members declared in class Any, but implementations may add host-specific methods to these classes (for instance, an implementation may identify class AnyRef with its own root class for objects).

There are currently three actively-maintained Implementations of Scala, and one abandoned one.

The abandoned Implementation of Scala is Scala.NET, which was a compiler targeting the Common Language Infrastructure. It was abandoned due to lack of interest and funding. (Basically, all the users that probably would have used Scala.NET were already using F#.)

The currently maintained Implementations of Scala are:

  • Scala-native: a compiled Implementation targeting unixoid Operating Systems and Windows.
  • Scala.js: a compiled Implementation targeting the ECMAScript and Web platform.
  • Scala (a rather unfortunately confusing name, because it is the same as the language): a compiled Implementation targeting the Java platform. And by "Java platform", I mean the Java Virtual Machine and the Java Runtime Environment but not the Java Programming Language.

All three Implementations are written 100% in Scala. Actually, they are not three fully independent implementations, they use the same compiler frontend with only different backends, and they use the same parts of the Scala Standard Library that are written in Scala, and only re-implement the parts written in other languages.

So, what is true is that the Java Implementation of Scala does indeed do something with java.lang.Object. However, java.lang.Object is not the superclass of scala.Any. In fact, it can't be because scala.Any is the root superclass of both reference types and value types, whereas java.lang.Object is only the root superclass of all reference types. Therefore, java.lang.Object is actually equivalent to scala.AnyRef and not to scala.Any. However, java.lang.Object is not the superclass of scala.AnyRef either, but rather, both are the same class.

Also, java.lang._ is automatically imported just like scala._ is. But this does not apply to the Scala Programming Language, it only applies to the Java Implementation of the Scala Programming Language, whose name is unfortunately also Scala.

So, only for one of the three Implementations, there is some truth to the statement that java.lang.Object is the root class, but it is not a superclass of scala.Any, rather it is the same class as scala.AnyRef.

But again, this is only true for the Java Implementation of Scala. For example, in Scala.NET, the root superclass would be identified with System.Object, not java.lang.Object, and it would be equivalent to scala.Any, not scala.AnyRef because the CLI has a unified type system like Scala where reference types and value types are unified in the same type system. And I haven't checked Scala.js, but I would assume that it would identify Object with scala.AnyRef.

Note, however, that none of this is because the Implementation is "built off" something. The reason for doing this, for trying to merge the Scala and Java / CLI / ECMAScript class hierarchy, is for interoperability, it is for making it easy to call Scala code from every other language on the Java / CLI / ECMAScript platform, and vice versa, call code written in other languages from Scala. If you didn't care about that, then there would be no need to jump through these hoops.

Upvotes: 3

Mario Galic
Mario Galic

Reputation: 48420

java.lang.Object is not the parent of scala.Any. Consider the following relationships

implicitly[Any <:< java.lang.Object]     // error
implicitly[AnyVal <:< java.lang.Object]  // error
implicitly[AnyRef <:< java.lang.Object]  // ok

However, say you had the following Java class

public class Foo {
    public void bar(Object o) {}
    public void zar(int o) {}
    public void qux(java.lang.Integer o) {}
}

then all of the following would still work when called from Scala

val foo = new Foo
foo.bar(42.asInstanceOf[Int])
foo.bar(42.asInstanceOf[Any])
foo.bar(42.asInstanceOf[AnyVal])
foo.bar(42.asInstanceOf[AnyRef])
foo.zar(42) // zar takes primitive int
foo.qux(42) // qux takes java.lang.Integer

Upvotes: 1

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