CODEWITHSUNDEEP
phpregexvalidation
anvd
anvd

Reputation: 4047

regex for currency (euro)

i am trying this code for make a validation for a value. (regex from this site)

UPDATE:

Now i have

$value1=250;    

$value2=10000;

        if (!preg_match("/^(([^0]{1})([0-9])*|(0{1}))(\,\d{2}){0,1}€?$/", $form['salary']) || (!$form['salary'])>$value1."€" && (!$form['salary'])<$value2."€" ){
        echo ("invalido");
        return false;
    }
    else
    echo ("valido");
    return true;

the code works well, but 20€ is accepted, so the problem now is not the regex, but compare values like 200€ or 1000€.

this probably is wrong

(!$form['salary'])>$value1."€"

example some Input values:

    200€
    200
    200.5
    200.50€

limits - 250€ to 10000€

thanks

Upvotes: 1

Views: 10730

Answers (3)

user1237981
user1237981

Reputation: 165

My contribution. It works great.

final Pattern pattern = Pattern.compile("^([0-9]+)|((([1-9][0-9]*)|([0-9]))([.,])[0-9]{1,2})$");

Upvotes: 0

anvd
anvd

Reputation: 4047

This code below solved my problem:

if (!preg_match("/^(([^0]{1})([0-9])*|(0{1}))(\,\d{2}){0,1}€?$/", $form['salary'])) {
    echo "invalid";
    return false;
} else {
    $value1 = 400;
    $value2 = 10000;
    $salary = $form['salary'];
    $salary = preg_replace('/[€]/i', '', $salary);
    if($salary < $value1 || $salary > $value2) {
        echo "bad values";
        return false;
    } else {
        echo "valid";
        return true;
    }
}

Upvotes: 3

stema
stema

Reputation: 93046

The regex solution would look like this

^(?:10000|(?:(?:(?:2[5-9]\d)|[3-9]\d{2}|\d{4})(?:[,.]\d{2})?))€?$

See here online on Regexr

But it would be better for checking if a value belongs to a range, not to use a regex. You can extract the value easily and do a normal <> check on numbers outside.

Upvotes: 1

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