Reputation: 67
Answer is here.
I have the following points in a cartesian plane
points = [(4, 5), (-0, 2), (4, 7), (1, -3), (3, -2), (4, 5), (3, 2), (5, 7), (-5, 7), (2, 2), (-4, 5), (0, -2), (-4, 7), (-1, 3), (-3, 2), (-4, -5), (-3, 2), (5, 7), (5, 7), (2, 2), (9, 9), (-8, -9)]
And I need to find the closest point to the center using the Euclidean distance.
So far a I have done this:
import math
euclidean_distance=[]
distance = math.sqrt(sum([((x+y)**2) for (x,y) in points]))
for (x,y) in points:
int(distance)
euclidean_distance.append(distance)
min_distance=min(euclidean_distance)
print(distance)
print(euclidean_distance)
print(min_distance)
and the results are:
38.71692136521188
[38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188, 38.71692136521188]
38.71692136521188
Why is not calculating the Euclidean distance in each point of the list?
Upvotes: 2
Views: 2056
Reputation: 67
Finally I did this and worked for me:
import math
distance_points=[]
def euclidean_distance (points):
return math.sqrt((x**2+y**2))
for (x,y) in (points):
distance=euclidean_distance(points)
distance_points.append(distance)
print(distance_points)
Upvotes: 1