CODEWITHSUNDEEP
python
delalma
delalma

Reputation: 928

Type in list comprehension send 'None'

Can somebody explain why list is supposed to allow mix types but the following code does not work please (the only difference is the type declaration around the i?

The error:

print(','.join([buzzfizz(n) for n in range(1,51)]))
TypeError: sequence item 0: expected str instance, int found

DO NOT WORK:

def buzzfizz(i):
        if i % 2 == 0:
            return 'buzz'
        if i % 3 == 0:
            return 'fizz'
        if (i % 3 == 0 & i % 2 == 0):
            return 'buzzfizz'
        else:
            return i

print(','.join([buzzfizz(n) for n in range(1,51)]))

WORK:

def buzzfizz(i):
        if i % 2 == 0:
            return 'buzz'
        if i % 3 == 0:
            return 'fizz'
        if (i % 3 == 0 & i % 2 == 0):
            return 'buzzfizz'
        else:
            return str(i)

print(','.join([buzzfizz(n) for n in range(1,51)]))

Upvotes: 1

Views: 35

Answers (1)

one
one

Reputation: 2585

That's because the ','.join() need a list whose elements is str type. In your first code, the last return i is not a str type.

Upvotes: 3

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