CODEWITHSUNDEEP
pythonarrays
user12887858
user12887858

Reputation:

Appending to arrays in python

I am new to python and trying to append characters of a card number to two different arrays. 4003600000000014 every other digit, starting with the number’s second-to-last digit so the first digit is 1(that is left of the 4) and by jumping one number going all the way to the 0. After that, numbers that did NOT appended to the first array (mbt) should be appended to the 2nd array(normal).

mbt should be like = 4 0 6 0 0 0 0 1 normal should be like = 0 3 0 0 0 0 0 4 (two arrays combined will be again equal to 4003600000000014)

import math


def digitnumber(n):
    if n > 0:
        digits = int(math.log10(n)) + 1
        return digits


def isvalid(n, mbt=[], normal=[]):
    cardnumber = 4003600000000014
    dnumber = digitnumber(4003600000000014)
    n = dnumber - 1,
    mbt = []
    while 1 <= n < dnumber:
        x = int(cardnumber / pow(10, n) % 10)
        mbt.append(x)
        n -= 2
        n = dnumber - 2
        normal = []
        while 1 <= n < dnumber:
            x = int(cardnumber / pow(10, n) % 10)
            normal.append(x)
            n -= 2


def main():
    mbt = []
    normal = []
    isvalid(4003600000000014, mbt=[], normal=[])
    print(len(mbt))


main()

Upvotes: 0

Views: 101

Answers (3)

Red
Red

Reputation: 27547

You can use this function:

def split(num):
    num = [n for n in str(num)]
    num1 = []
    num2 = []
    for n in range(len(num)//2): # Move all element from num to num1 and num2. Since we are moving elements from 1 list to 2 lists, divide by two to distribute evenly. If the number of elements in num is odd, the // will get get rid of the decimal part
        num1.append(num.pop()) # Removes last element from num and adds it to num1
        num2.append(num.pop()) # Removes last element from num and adds it to num2
    if num: # If there is still an element left (as in, the number of elements in num was odd to begin with):
        num1.append(num.pop()) # Move that element to num1

    return ' '.join(reversed(num1)),' '.join(reversed(num2))

print(split(4003600000000014))

Output:

('0 3 0 0 0 0 0 4', '4 0 6 0 0 0 0 1')

Upvotes: 0

alec_djinn
alec_djinn

Reputation: 10789

Assuming that your input is an integer and you expect 2 lists of integers as output:

x = 4003600000000014
x = list(str(x))
a = list(map(int, x[1::2]))
b = list(map(int, x[0::2]))

print(a)
print(b)

[0, 3, 0, 0, 0, 0, 0, 4]
[4, 0, 6, 0, 0, 0, 0, 1]

Upvotes: 0

Kassym Dorsel
Kassym Dorsel

Reputation: 4843

From what I understand you are trying to slice number to get individual digits. You can find more information on slicing in Python: Understanding slice notation

Here's a solution using python slicing to the problem. The output arrays can be reversed as needed.

def isvalid(n):
    string_num = str(n)
    mbt = [int(x) for x in string_num[1::2]]
    normal = [int(x) for x in string_num[0::2]]
    return mbt, normal


def main():
    mbt, normal = isvalid(378282246310005)
    print(len(mbt))


main()

Upvotes: 2

Related Questions