CODEWITHSUNDEEP
sparqldbpedia
cyr
cyr

Reputation: 65

DBpedia SPARQL and predicate connection

I've got a problem with the DBpedia SPARQL endpoint because the properties of the properties like the label of rdf:type are not stocked in the endpoint. So when I run this query:

SELECT * 
WHERE{
  <http://dbpedia.org/ontology/Place> ?predicat ?object .
  OPTIONAL{?predicat rdfs:label ?label}
}

I've got nothing for ?label.

If someone got any idea to solve this problem it would be very helpful.

Upvotes: 3

Views: 436

Answers (2)

cygri
cygri

Reputation: 9472

You can't get the real labels from DBpedia because the SPARQL endpoint doesn't have them. But you can take the local name of the property URI. So, for rdfs:subClassOf you'd get "subClassOf". That's better than nothing. This can be done using Virtuoso's (non-standard) bif:regexp_replace function.

SELECT DISTINCT (bif:regexp_replace(STR(?p), "^.*[/#]", "") AS ?label) WHERE {
   <http://dbpedia.org/ontology/Place> ?p ?o .
}

Upvotes: 2

glenn mcdonald
glenn mcdonald

Reputation: 15478

I don't think there's a SPARQL solution. Dbpedia doesn't have the data you want, and I couldn't easily find a SPARQL endpoint for that RDF at W3C. And I don't think the Virtuoso dbpedia endpoint supports federation yet, even if we did find a SPARQL endpoint for W3C.

Happy to be proven wrong on any of those points.

Upvotes: 0

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