CODEWITHSUNDEEP
exceptionassemblyx86-64interruptinterrupt-handling
Arush Agarampur
Arush Agarampur

Reputation: 1420

How would an empty interrupt service handler be written in x64?

I have read the AMD64 Developer manual on interrupt routines. According to the manual,

The interrupt handler must pop the error code off the stack if one was pushed by the interrupt or exception. IRET restores the interrupted program's rIP, CS and rFLAGS by popping their saved values off of the stack and into their respective registers.

Therefore, would an empty ISR handler look something along this ASM code?

add rsp, 4       ;pop err code off stack
iretq

I am assuming the size of the error code is 4 bytes, as other websites have told me. I'm pretty sure this is totally wrong, but some guidance will help.

Upvotes: 1

Views: 778

Answers (1)

Arush Agarampur
Arush Agarampur

Reputation: 1420

The error code size in long-mode (x64) is 8 bytes long. So instead of adding 4 bytes to the stack pointer, you will need to add 8 bytes.

In addition, not all exceptions push an error code onto the stack. A table that contains which exceptions do and do not can be found here: https://wiki.osdev.org/Exceptions

If a hander does not push an error code, the empty handler is just the iretq instruction to return from the handler. If it DOES push an error code, we simply add 8 bytes to the stack pointer and then return from the handler.

add rsp, 8
iretq

Thanks @MichaelPetch

Upvotes: 4

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