CODEWITHSUNDEEP
pythonfor-loop
Anna
Anna

Reputation: 19

Write a for loop that iterates over to_ten and prints out whether the number is even or odd

to_ten=['1','2','3','4','5','6','7','8','9','10']

for i in range(10):

    if i %2==0:
        i='Number is even'
    else: i='Number is odd'
print(i)

Create a list called to_ten containing the numbers from 1-10.Write a for loop that iterates over to_ten and prints out whether the number is even or odd. Please help me understand how to get a statement for each number in the 1-10 list about whether it is even or odd.

Upvotes: 0

Views: 1242

Answers (3)

cdlane
cdlane

Reputation: 41872

There are three issues with your code: first, you substitute a range() for to_ten so don't actually implement the problem as stated; you make to_ten a list of str instead of a list of int; your print(i) statement is in the wrong order and at the wrong indentation. The solution of @biplobbiswas does a nice job of addressing all of these minor issues. (+1)

We can simplify the problem by making to_ten a list of int, and have Python generate it for us, to avoid errors. We can also use the result of i % 2 as an index rather than test it explicitly with a series of if statements:

to_ten = [*range(1, 11)]  # a list containing the numbers from 1-10

for number in to_ten:
    print("{} is {}".format(number, ['even', 'odd'][number % 2]))

There are numerous ways to go about a problem like this.

Upvotes: 0

Red
Red

Reputation: 27567

Your code is almost correct,

but you need to indent the print statement in order for the program to print the number in each iteration.

And, range(num) will begin at 0, and the num will not be included in the iteration.

[1,2,3,4,5,6,7,8,9,10] is equivalent to range(1,11) in python.

for i in range(1,11):
    if i % 2 == 0: # If the number divided by two leaves no remainder:
        print(f'{i} is even')
    else:
        print(f'{i} is odd')

Output:

1 is odd
2 is even
3 is odd
4 is even
5 is odd
6 is even
7 is odd
8 is even
9 is odd
10 is even

Upvotes: 0

biplob biswas
biplob biswas

Reputation: 104

to_ten=['1','2','3','4','5','6','7','8','9','10']

for i in to_ten:
    if int(i)%2 == 0:
        print(f'{i} is even')
    else:
        print(f'{i} is odd')

Out:

1 is odd
2 is even
3 is odd
4 is even
5 is odd
6 is even
7 is odd
8 is even
9 is odd
10 is even

Upvotes: 1

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