CODEWITHSUNDEEP
pythondictionary
Nelson
Nelson

Reputation: 37

Find values within lists in dictionary

I was given this list with historical scores of games from a popular college team (Oregon Ducks):

[
    '1916-10-07,1916,Willamette,97,0\n',
    '1916-10-14,1916,Multnomah A.C.,28,0\n',
    '1916-10-21,1916,California,39,14\n',
    '1916-11-04,1916,Washington,0,0\n',
    '1916-11-11,1916,Washington State,12,3\n',
]

I wrote code to extract the season, duck's scores, and allowed scores and put them in a dictionary:

def parse_football_data(lst):

    DUCKS = {
        'season': [int(i.split(',')[1]) for i in lst],
        'scored': [int(i.split(',')[3]) for i in lst],
        'allowed': [int(i.split(',')[4].strip()) for i in lst],
    }
    return DUCKS

Which has this output:

{'season': [1916, 1916, 1916, 1916, 1916],
 'scored': [97, 28, 39, 0, 12],
 'allowed': [0, 0, 14, 0, 3]}

I now need to write a function def total_by_year(games, year): which will give me the sum of scores for the input year, and the opposing's team allowed scores in this format:

total_by_year(dct, 1916)
(51, 17)

when I input this using my previous function:

dct = parse_football_data([
    '1916-10-21,1916,California,39,14\n',
    '1916-11-04,1916,Washington,0,0\n',
    '1916-11-11,1916,Washington State,12,3\n',
    '1917-11-17,1917,California,21,0\n',
    '1917-11-29,1917,Oregon State,7,14\n'
])

How can I match the year to the "season" and "allowed" keys in the dictionary?

Upvotes: 0

Views: 45

Answers (1)

Mark
Mark

Reputation: 4455

This sounds a lot like homework. Nonetheless, consider this example implementation of total_by_year(). 

def total_by_year(dct, year):

  scored = 0
  allowed = 0

  for (index,season) in enumerate( dct['season'] ):
    if season == year:
      scored += dct['scored'][index]
      allowed += dct['allowed'][index]


  return ( scored, allowed )

Upvotes: 1

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