CODEWITHSUNDEEP
javascriptarraysfilter
mg2019
mg2019

Reputation: 309

JS: Filter list of objects to include only the strings found in second array

I have an array of objects similar to the following:

let array = [
{
id: 1,
name: Foo,
tools: [{id:3, toolname: Jaw},{id:1, toolname: Law}]
},
{
id: 2,
name: Boo,
tools: [{id:2, toolname: Caw}]
},
{
id: 3,
name: Loo,
tools: [{id:3, toolname: Jaw}, {id:4, toolname: Maw}, {id:6, toolname: Taw}]
}
]

I have a second array that looks like the following:

let secondarray = ['Jaw', 'Taw']

How can I return a list of objects that include only BOTH of the items in the second array? So if an object only has one of the two, the object would not be included. In addition, if the object contains other tools not in the secondarray, but includes both items in the secondarray, it should still be included.

Thus the expected output of this filter would be:

{
id: 3,
name: Loo,
tools: [{id:3, toolname: Jaw}, {id:4, toolname: Maw}, {id:6, toolname: Taw}]
}

Thank you for your time!

Upvotes: 1

Views: 43

Answers (1)

Nina Scholz
Nina Scholz

Reputation: 386600

You could iterate the data array and then check if all of the reqired tools are in the actual object.

let array = [{ id: 1, name: 'Foo', tools: [{ id: 3, toolname: 'Jaw' }, { id: 1, toolname: 'Law' }] }, { id: 2, name: 'Boo', tools: [{ id: 2, toolname: 'Caw' }] }, { id: 3, name: 'Loo', tools: [{ id: 3, toolname: 'Jaw' }, { id: 4, toolname: 'Maw' }, { id: 6, toolname: 'Taw' }] }],
    required = ['Jaw', 'Taw'],
    result = array.filter(({ tools }) =>
        required.every(v => tools.some(({ toolname }) => toolname === v))
    );

console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }

Another approach to omit the loop over tools more than once by using a Set.

let array = [{ id: 1, name: 'Foo', tools: [{ id: 3, toolname: 'Jaw' }, { id: 1, toolname: 'Law' }] }, { id: 2, name: 'Boo', tools: [{ id: 2, toolname: 'Caw' }] }, { id: 3, name: 'Loo', tools: [{ id: 3, toolname: 'Jaw' }, { id: 4, toolname: 'Maw' }, { id: 6, toolname: 'Taw' }] }],
    required = ['Jaw', 'Taw'],
    result = array.filter(({ tools }) => 
        required.every(
            Set.prototype.has,
            new Set(tools.map(({ toolname }) => toolname))
        )
    );

console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }

Upvotes: 2

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