Reputation: 545
7 years ago I would write something like that:
#include <iostream>
struct A {};
struct B {
static const char* message;
};
const char* B::message = "Hello, world!";
template <typename T>
void PrintMessage(...) {}
template <typename T>
void PrintMessage(decltype(&T::message)) {
std::cout << T::message << std::endl;
}
int main() {
PrintMessage<A>(nullptr);
PrintMessage<B>(nullptr);
return 0;
}
The solution would work even with Visual C++ 2010 if I recall correctly. Is there any better way of doing that in C++ 17 ?
Upvotes: 4
Views: 1158
Reputation: 4046
If you know which function or member you would like to check you can create a type_trait
template<class T, class = void>
struct has_message : std::false_type { };
template<class T>
struct has_message<T, std::void_t<decltype(T::message)>> : std::true_type { };
template<class T>
void PrintMessage()
{
if constexpr (has_message<T>::value)
std::cout << T::message << std::endl;
}
Upvotes: 11