CODEWITHSUNDEEP
pythonpython-3.xinfinite
Ovidiu Leonte
Ovidiu Leonte

Reputation: 45

I need to represent infinite as integer in python 3

I'm working in Python 3, Windows 10, PyCharm.

I'm building a small program that lets you input your age and returns "Happy {age}{termination, eg: st, nd}!"

The thing is that I want to somehow avoid the situation where you will write your age as 1041 and it'll say "Happy 1041th!". So I used list(range(21, 1001, 10)) for the termination "st", for instance. However, I'd like to be able to use infinite instead of 1001. If I use math.inf, that's a float and it's not accepted in my code. Also, I can't convert it to int.

I'm thinking of using a n number that should be higher than say, 100, and have list(range(21, n, 10)), but I'm too much of a beginner to know how to do that. Thanks for the help. Here's my code:

age = int(input('Type age: '))
if int(age) == 1:
    term = 'st'
elif int(age) == 2:
    term = 'nd'
elif int(age) == 3:
    term = 'rd'
elif int(age) in list(range(21, 1001, 10)):
    term = 'st'
elif int(age) in list(range(22, 1002, 10)):
    term = 'nd'
elif int(age) in list(range(23, 1003, 10)):
    term = 'rd'
else:
    term = 'th'
if int(age) >= 130:
    print("C'mon! you can't be THAT old, you geezer!\nStill, here you go:")
message = f"Happy {age}{term} birthday!"

print(message)

Upvotes: 1

Views: 578

Answers (3)

Transamunos
Transamunos

Reputation: 101

You don't need change to be list, if you change it to be list it may will be error. You just input age in range(s, e, i). If you want higher like as infinity use like this age in range(21, sys.maxsize**100, 10)

import sys
inf = sys.maxsize**10
age = int(input('Type age: '))
if int(age) == 1: term = 'st'
elif int(age) == 2: term = 'nd'
elif int(age) == 3: term = "rd"
elif int(age) in range(21, inf, 10): term = 'st'
elif int(age) in range(22, inf, 10): term = "nd"
elif int(age) in range(23, inf, 10): term = 'rd'
else: term = 'th'

if int(age) >= 130:
    print("C'mon! you can't be THAT old, you geezer!\nStill, here you go:")
message = f"Happy {age}{term} birthday!"
print(message)

But, why you want to use range if there is easier than it? Like make it to be string and then check the last number.

age = int(input("Type age: "))
term = ["st", "nd", "rd", "th"][3 if age%10 > 3 or age%100 in range(10, 20) else age%10-1]
if age > 130: message = "blah-blah-blah"
print(message)

Yes, I know the result is defferent. But, the next code I show you it's also can handle higher than hundred. Such as 101, on your code will be 101th; I think isn't correct. Variable term I have input ternary operator or conditional expression. In Python [if_true] if [condition] else [if_false] In JS condition? if_true:if_false

Looping from 1 to infinity in Python

Upvotes: 1

Axe319
Axe319

Reputation: 4365

There is no reason to check membership in a massive list which will eat up a ton of memory. You can just check what you age endswith.

age = input('Type age: ')
if age.endswith('11') or age.endswith('12') or age.endswith('13'):
    term = 'th'
elif age.endswith('1'):
    term = 'st'
elif age.endswith('2'):
    term = 'nd'
elif age.endswith('3'):
    term = 'rd'
else:
    term = 'th'

if int(age) >= 130:
    print("C'mon! you can't be THAT old, you geezer!\nStill, here you go:")
message = f"Happy {age}{term} birthday!"

print(message)

Upvotes: 3

Nick
Nick

Reputation: 147156

Modulo arithmetic is a better (and completely general) solution to this problem:

age = int(input('Type age: '))
if 11 <= (age % 100) <= 13:
    term = 'th'
elif age % 10 == 1:
    term = 'st'
elif age % 10 == 2:
    term = 'nd'
elif age % 10 == 3:
    term = 'rd'
else:
    term = 'th'
if age >= 130:
    print("C'mon! you can't be THAT old, you geezer!\nStill, here you go:")
message = f"Happy {age}{term} birthday!"

print(message)

Upvotes: 3

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