CODEWITHSUNDEEP
pythonpandas
william007
william007

Reputation: 18547

Getting first values with index in Series

Given

import pandas as pd
df = pd.DataFrame({'lowercase':['a','b','c','d']},
                       index=[0,1,3,4])

# print(df)

print(df['lowercase'].iat[0])

I can get 'a', but I want to get the first index (which is 0) and 'a' return as two values, how should I do?

Upvotes: 0

Views: 215

Answers (1)

Ch3steR
Ch3steR

Reputation: 20689

You can use df.itertuples which returns a map object.

def get_item(idx):
    it = df.itertuples()
    while idx:
        next(it)
        idx = idx-1
    return next(it)

a,b = get_item(0)
# a = 0 , b = 'a'
c,d = get _item(1)
# c = 1, d = 'b'

You can even get a slice using islice from itertools.

def get_item(start,end=None):
    it = df.itertuples()
    if end is None:
        while idx:
            next(it)
            idx = idx-1
        return next(it)
    return list(map(tuple,islice(it,start,end)))

get_item(1, 4)
# [(1, 'b'), (3, 'c'), (4, 'd')]

If you only want first value

a,b = next(df.itertuples())
# a = 0, b = 'a'

Upvotes: 1

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