Reputation: 23
I'm trying to make a sudoku solver using backtracking and I ran into a problem. Whenever I change a copy of the grid array, the original changes too.
Can someone help me please?
The algorithm:
let grid = [
[0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0],
];
// make a copy of the grid
let newGrid = [...grid];
// a vqriable that becomes true if we find a solution to the puzzle
let found = false;
// this function checks if the current choice for grid[row][col] is valid
const valid = (row, col) => {
// check the row for the same number
for (let j = 0; j < 9; j++)
if (newGrid[row][col] === newGrid[row][j] && j !== col) return false;
// check the column
for (let i = 0; i < 9; i++)
if (newGrid[row][col] === newGrid[i][col] && i !== row) return false;
// check the smaller "box"
// the number of the box that the current element is in
const verticalNumber = Math.floor(row / 3);
const horizontalNumber = Math.floor(col / 3);
// iterate through the whole grid
for (let i = 0; i < 9; i++)
for (let j = 0; j < 9; j++) {
const vertical = Math.floor(i / 3);
const horizontal = Math.floor(j / 3);
// if the elements are not in the same box or the element is the current element, skip it
if (
vertical !== verticalNumber ||
horizontal !== horizontalNumber ||
(i === row && j === col)
)
continue;
if (newGrid[i][j] === newGrid[row][col]) return false;
}
// otherwise it's okay
return true;
};
// this function checks if the algorithm is finished
const stop = (row, col) => {
return row > 8;
};
const backtracking = (row, col) => {
if (found) return;
// if the algorithm finished, print the completed puzzle
if (stop(row, col)) {
console.log(newGrid);
found = true;
return;
}
// if the current cell already has a number, skip it
if (grid[row][col]) {
if (col === 8) backtracking(row + 1, 0);
else backtracking(row, col + 1);
// otherwise check every single posibility, and if it is valid go to the next cell
} else {
for (let i = 1; i <= 9 && !found; i++) {
newGrid[row][col] = i;
console.log(newGrid[row][col] === grid[row][col]);
if (valid(row, col)) {
if (col === 8) backtracking(row + 1, 0);
else backtracking(row, col + 1);
}
}
}
};
backtracking(0,0);
I looked it up online and couldn't find any other answer than "use ... or slice", which I did, as you can see.
Upvotes: 2
Views: 307
Reputation: 4241
For your specific problem try this (shallow copy of each row is sufficient for your use case):
let grid = [
[0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0],
];
// make a copy of the grid
let newGrid = grid.map(row => [...row]);
//mutate original grid:
grid[0][1] = 1;
//newGrid is not affected by above mutation
console.log("old", grid, "new", newGrid);
Upvotes: 1
Reputation: 1485
The problem is that the arrays inside newGrid
are still the original arrays, you are just changing what array they are apart of. Try using .map()
...
newGrid = grid.map(r => [...r])
Upvotes: 2
Reputation: 169378
Because
let newGrid = [...grid];
makes a shallow copy, and the sub-arrays aren't copied. You'll need a deep copy; for a simple array like this, an ugly and slow (but easy and effective) way is to round-trip via JSON:
let newGrid = JSON.parse(JSON.stringify(grid));
If you don't want to do that, e.g. Lodash comes with a cloneDeep()
function.
Upvotes: 5