CODEWITHSUNDEEP
htmldjangodjango-templates
Bibin M
Bibin M

Reputation: 63

If condition in django templates not working

I have tried the if condition based on the value defined in the django template

{% if randomgen == 2 %}
<p style="float:right;text-align: center;padding:5px 5px;"><b>{% randomgen %}1</p>
{% else %}
<p style="float:right;text-align: center;padding:5px 5px;"><b>{% randomgen %} 2</p>
{% endif %}

the randomgen is defined to pick in random between 1 and 2 and the value is being displayed correctly in

tag but irrespective of the value it always going to else condition

register = template.Library()

@register.tag(name="randomgen")
def randomgen(parser, token):
    items = []
    bits =  token.split_contents()
    for item in bits:
        items.append(item)
    return RandomgenNode(items[1:])

    def render(self, context):
        arg1 = 0
        arg2 = 10
        if "float" in self.items:
            result = random.randint(1,20)
        elif not self.items:
            result = random.randint(1,20)
        else:
            result = random.randint(1,2)
        return result

Upvotes: 4

Views: 1229

Answers (1)

Zenon Anderson
Zenon Anderson

Reputation: 84

In your HTML, set randomgen to another variable:

{% randomgen as rgen %}

Then use the newly set variable for your conditional:

{% if rgen == 2 %}

Honestly, I was surprised your code didn't work as your usage makes sense intuitively. Knowing that it doesn't work though, my guess is the template is comparing a function with an integer which is always going to return False. Good question!

Upvotes: 3

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