Reputation: 2418
I want to be able to say make an instance of this class and give a type then the code can instantiate a new instance of that class.
fun maker(type: Class<Animal>): Animal {
if(type == Class<Dog>) {
return Dog()
}
else if (type == Class<Cat>) {}
...
}
What is a good way to do this?
Upvotes: 0
Views: 558
Reputation: 13571
If the function can be inline
you can also use reified type
inline fun<reified T: Animal> make() = T::class.createInstance()
...
val dog = make<Dog>()
Please notice that to use createInstance()
the class must have no-arg constructor or IllegalArgumentException
will be thrown
Upvotes: 0
Reputation: 555
(Updated) I am not an expert in Kotlin but you can do something like this :
import kotlin.reflect.KClass
import kotlin.reflect.full.createInstance
class A {
fun greet() {
println("Hello A");
}
}
class B{
fun greet() {
println("Hello B");
}
}
fun <T : Any> maker(clazz: KClass<T>): T {
return clazz.createInstance();
}
val aObj = maker<A>(A::class);
aObj.greet();
val bObj = maker<B>(B::class);
bObj.greet();
Output:
Hello A
Hello B
I hope now it makes sense you just need to pass the class to the method and it returns an object.
As you will be using Animal as a parent class so you can replace Any => Animal
fun <T : Animal> maker(clazz: KClass<T>): T {
return clazz.createInstance();
}
Upvotes: 0
Reputation: 93561
If they all have zero-argument constructors, you can do:
fun maker(type: Class<Animal>): Animal {
return type.newInstance()
}
You can make it return the type that was passed in for a little more versatility:
fun <T: Animal> maker(type: Class<T>): T {
return type.newInstance()
}
Upvotes: 2
Reputation: 544
Correct version following your example (not sure if best approach overall):
fun <T: Animal> maker(type: Class<T>): T? {
return when (type) {
Cat::class.java -> Cat() as T
Dog::class.java -> Dog() as T
else -> null
}
}
And then to create objects:
val a = maker(Cat::class.java)
val b = maker(Dog::class.java)
Upvotes: 1