CODEWITHSUNDEEP
phplaravelexceptionerror-handling
Symphony0084
Symphony0084

Reputation: 1435

How to use report() function with a specific channel in Laravel?

You can define your log channels in config/logging.php as I have already done.

Then you can send a log to your new channel like this: 

Log::channel('my-channel')->error('message');

Now, when I want to catch an exception without throwing it, I usually use the report() helper function like this:

try{
   throw new Exception('message');
}catch(Exception $e){
   report($e);
}

That is very useful for continuing a script after an exception is thrown, but it always logs the exception to my default logging channel.

I want to use the report() function and specify that it should be reported to my-channel.

I played around with app/Exceptions/Handler.php without any luck.

Upvotes: 0

Views: 1469

Answers (1)

Symphony0084
Symphony0084

Reputation: 1435

So far I decided to just make a simple class to emulate report() instead of trying to use it directly:

<?php

namespace App\Exceptions;

use Log;
use Throwable;

class Reporter
{
    /**
     * Reports an exception to a specific channel.
     * 
     * @param Throwable $e
     * @param string $channel
     * @param array $context
     */
    public static function report(Throwable $e, $channel = 'daily', $context = [])
    {
        Log::channel($channel)->error(
            $e->getMessage(),
            array_merge(
                Context::getContext(),
                $context,
                ['exception' => $e],
            )
        );
    }
}

And you would use it like this:

try{
   throw new Exception('message');
}catch(Exception $e){
   Reporter::report($e, 'my-channel');
}

You can also pass extra context to the log message as an array.

Upvotes: 4

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